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Virty [35]
2 years ago
6

How many nickels are in 25.2 dollars

Mathematics
2 answers:
frosja888 [35]2 years ago
7 0

1 nickel = 0.05

25.2/0.05 = 504 nickels

777dan777 [17]2 years ago
7 0
There should be 504 nickels in 25.2 dollars. Hope this was helpful.
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A snowstorm began on Monday evening. It snowed steadily until 6:00 am on Tuesday morning when the snow was 12 inches deep. Kevin
poizon [28]

Answer:

what is expected at 7am is 15 inches deep snow but what we have is 12 inches deep snow. The equation has failed in its prediction.

Step-by-step explanation:

In this question, we are asked to calculate if the prediction made by an equation modeled is correct.

Firstly let’s look at the equation in question;

y = 3t - 6

where y is the snow depth and t is the number of hours after midnight.

now we are looking at 7am, that’s 7 hours past 12am, meaning 7 hours after midnight.

let’s plug the value of t as 7 into the equation

y = 3(7) - 6

y = 21-6

y = 15 inches

according to the equation by Kevin, what is expected is 15 inches deep snow but what we have is 12 inches deep snow. The equation has failed in its prediction.

3 0
3 years ago
Write the sentence as an equation.<br> 62 more than the product of 150 and r is 40
Elenna [48]

Answer:

150 • r + 62 = 40

Step-by-step explanation:

6 0
2 years ago
Make a conjecture about the sum of primes based on the following pattern:
Setler [38]
14= 7+7
16= 8+8
18= 9+9
20= 9+11
22= 10+12
24= 12+12
26= 7+8+11
6 0
2 years ago
GEOMETRY HELP) Triangle ABC is similar to triangle PQR. <br><br><br><br> Which equation is correct?
kirill115 [55]
Hello,

We must find the corresponding points: (using angles)

A-->P
B-->Q
C-->R

AB/PQ=BC/QR=AC/PR ===> c/r=a/p=b/q

Answer C




3 0
3 years ago
Which of the following can be used to calculate the volume of water inside the fish bowl?
Lunna [17]

The volume of a sphere can be calculated as

V=\frac{4}{3}\pi r^3

Where r is the radius of the sphere

We want to calculate half of the volume, then we must divide that volume by 2

V^{\prime}=\frac{1}{2}\frac{4}{3}\pi r^3

Now we must find the radius of our sphere, the segment AB is the diameter of the sphere, and the radius is half od the diameter, then

r=\frac{AB}{2}=\frac{12}{2}=6

Let's put it into our equation

\begin{gathered} V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)(\pi)(r)^3 \\  \\ V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)(\pi)(6)^3 \end{gathered}

The problem says to use

\pi\approx\frac{22}{7}

Then

V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)\left(\frac{22}{7}\right)(6)^3

Final answer:

The formula that can be used to calculate the volume of water inside the fish bowl is

V=\frac{1}{2}\left(\frac{4}{3}\right)\left(\frac{22}{7}\right)(6)^3

8 0
1 year ago
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