Answer:
<h2>
</h2>
Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about</h3>
- area of triangles
- area of rectangle
- PEMDAS
<h3>tips and formulas:</h3>
- rectangle opposite sides are equal
- area of rectangle:l×w
- area of triangle:½×h×b
<h3>let's solve:</h3>
the area of the rectangle is
4×7 in²
28 in²
the area of above triangle is
½×6×7 in²
3×7 in²
21 in²
the area of left side triangle is
½×5×4 in²
2×5 in²
10 in²
therefore,
the area of the polygon is
28+21+10 in²
<h3>59 in²</h3>
Answer:
y = 1/3x - 3
Step-by-step explanation:
If the line is perpendicular to y = -3x + 11, it means that the two gradients multiply to make -1.
So the gradient of the perpendicular line is 1/3 (-3 × 1/3 = -1)
y = 1/3x + c
Next, substitute x = -9, and y = -6 to find the y intercept, or c:
-6 = 1/3(-9) + c
-6 = -3 + c
c = -6 + 3
c = -3
The equation of the line is y = 1/3x - 3
Hope it help youuuuuuuuu <3
5x-3x^2/2x^4 =x(5-3x) / 2x.(x^3), simplified by x, we have <span>5-3x/2x^3, (x≠0)
</span>so the answer is <span>C.5-3x/2x^3, (x≠0)</span>
Width = ' W '
Length = 3 times as long = 3W
Area = (length) x (width) = (3W) x (W) = 3W²
