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geniusboy [140]
3 years ago
14

Based on the given segment lengths, determine whether the segments can form a triangle. 11.5,10.5, 6.1 9.5, 3.5, 4.5 8, 6.7, 1 8

, 6.7, 9.8 5, 6, 8 9.5, 7.5, 8.5
Mathematics
1 answer:
Viefleur [7K]3 years ago
6 0

Answer:

are you using edmentum ?

Step-by-step explanation:

lol

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(2x^3+6x-1)+(3x^2-7x)
sattari [20]

For this case we must simplify the following expression:

(2x ^ 3 + 6x-1) + (3x ^ 2-7x)

We eliminate the parentheses taking into account that:

+ * + = +\\+ * - = -

So, we have:

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We add similar terms taking into account that:

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Answer:

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7 0
3 years ago
Please help! Create a set of five positive numbers (repeats allowed) that have a median of 10 and a mean of 14. What thought pro
Brilliant_brown [7]
Alright, since there are 5 numbers, and the mean (or average) is (sum)/(amount of numbers), we have (sum)/5=14. Multiplying both sides by 5, we have the sum being 80. The median of 10 means that in a, b, c, d, e, 10 has to be c and the numbers have to be in ascending order. A and b must be 10 or lower, while d and e must be 10 or higher. Putting some random numbers in, we can have 1, 1, 10, 15, and e. We left e there because the sum needs to be 80, and since 1+1+10+15=27, 80-27=53=e. This, however, would not work if e was less than 10 and we therefore would have needed to make some numbers lower to compensate for this. Our answer is therefore 1, 1, 10, 15, 53
6 0
3 years ago
[4|16-38|+6]-17•2
Maurinko [17]

\bf \underset{\textit{we start from the innermost}}{\stackrel{\mathbb{PEMDAS}}{[4|16-38|+6]-17\cdot 2}}\implies [4\cdot |\stackrel{\downarrow }{-22}|+6]-17\cdot 2\implies [4\cdot \stackrel{\downarrow }{22}+6]-17\cdot 2 \\[2em] [\stackrel{\downarrow }{88}+6]-17\cdot 2\implies \stackrel{\downarrow }{94}-17\cdot 2\implies 94-\stackrel{\downarrow }{34}\implies 60

3 0
4 years ago
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