Answer:
1. A=300miles B=300
2.A=50mph B=40mph
3.A=300miles B=200miles
Step-by-step explanation:
<em><u>1.</u></em>
Simply just read the graph
<em><u>2.</u></em>
do not let line B fool you, car b may look like it was faster, but unlike car a it started at 100 miles rather than 0 miles
<em><u>3.</u></em>
Just like 2, do not be fooled, you have to subtract to find b but a is easily found
I hope this helps u pls give a brainliest and a thx ;)
9514 1404 393
Answer:
$935.11
Step-by-step explanation:
The amount is given by the formula ...
A = P(1 +r/n)^(nt) . . . P invested at rate r for t years compounded n per year
A = $850(1 +0.024/2)^(2·4) = $935.11
The amount accumulated will be $935.11 after 4 years.
Answer:
0.2364
Step-by-step explanation:
We will take
Lyme = L
HGE = H
P(L) = 16% = 0.16
P(H) = 10% = 0.10
P(L ∩ H) = 0.10 x p(L U H)
Using the addition theorem
P(L U H) = p(L) + P(H) - P(L ∩ H)
P(L U H) = 0.16 + 0.10 - 0.10 * p(L u H)
P(L U H) = 0.26 - 0.10p(L u H)
We collect like terms
P(L U H) + 0.10P(L U H) = 0.26
This can be rewritten as:
P(L U H)[1 +0.1] = 0.26
Then we have,
1.1p(L U H) = 0.26
We divide through by 1.1
P(L U H) = 0.26/1.1
= 0.2364
Therefore
P(L ∩ H) = 0.10 x 0.2364
The probability of tick also carrying lyme disease
P(L|H) = p(L ∩ H)/P(H)
= 0.1x0.2364/0.1
= 0.2364
Let’s call the speed of the slower car S, then the speed of the other is S+10mph.
At 5pm they have been travelling for 3 hours. The slower car travels a distance 3S and the faster one 3(S+10).
But the two distances must add up to 240 miles so 3S+3(S+10)=240, 3S+3S+30=240, 6S=210, S=35 mph. The faster car’s speed is 45mph. We can see that 3S is the same distance as 3x, so x=S=35 mph, and the distance the faster car travels is 3×45=135 miles.
