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Rufina [12.5K]
3 years ago
11

IF YOU HELP ME ILL GIVE YOU A MILLION BUCKS.

Mathematics
1 answer:
Len [333]3 years ago
5 0

Answer:

Here it is solved for rate:

log(1 + rate) = {log(total) -log(Principal)} ÷ Years

Let's work through your example:

log(1 + rate) = {log(6,680) -log(5,000)} / 6

log(1 + rate) = (3.8247764625 -3.6989700043) / 6

log(1 + rate) = 0.020967743

If we raise 10 to the 0.020967743 power

10^0.020967743  it produces 1 plus the rate

1 plus the rate = 10^0.020967743 = 1.0494644773

There fore the rate = .0494644773 which equals

4.94644773 per cent

Source:  https://www.1728.org/compint2.htm

Step-by-step explanation:

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marishachu [46]
We'll be assuming this is with simple interest.

now, a year has 12 months, thus in 18 months there are 18/12 years.

\bf ~~~~~~ \textit{Simple Interest Earned Amount}
\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &\$1050\\
P=\textit{original amount deposited}\to& \$1020\\
r=rate\to r\%\to \frac{r}{100}\\
t=years\to \frac{18}{12}\to &\frac{3}{2}
\end{cases}

\bf 1050=1020\left[ 1+r\left( \frac{3}{2} \right) \right]\implies \cfrac{1050}{1020}=1+r\left( \frac{3}{2} \right) \implies \cfrac{35}{34}=1+r\left( \frac{3}{2} \right)
\\\\\\
\cfrac{35}{34}-1=\cfrac{3}{2}r\implies \cfrac{1}{34}=\cfrac{3}{2}r\implies \cfrac{2\cdot 1}{3\cdot 34}=r\implies \cfrac{1}{51}=r
\\\\\\
r\%=100\cdot \cfrac{1}{51}\implies r\approx\stackrel{\%}{1.96078431372549}
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A medical researcher is studying the spread of a virus in a population of 1000 laboratory mice. During any week, there is a 90%
xxMikexx [17]

Answer:

1. How many will be infected next week

From the information, there are 1000 mice in the lab.

200 mice are infected. It is expected that 90% of the mice are expected to overcome the infection and 40% uninfected mice will be infected.

If 200 mice are infected, then number of uninfected mice is:

= 1000 - 200 = 800

90% of infected mice get cured. Out of 200 mice who are infected, the number of mice getting cures is:

N(E) = P(E)×N(S)

= 0.90*200

= 180

The number of mice still infected is 200 - 180 = 20

Out of 800 uninfected mice, 40% will get infected. Number of infected mice is:

N(E) = P(E) * N(S)

= 0.40 * 800

= 320

​Total number of infected mice is 320 + 20  = 340 . Thus, the number of infected mice next week is 340

2. How many will be infected in 3 weeks

After three week, the number of infected mice is 340. Therefore, the number of uninfected mice is 1000 - 340 = 660

Now, out of 340 mice, it is expected that 90% will recover. This indicates that 10% will remain infected. Then the number of infected mice is

N(E) = P(E) * N(S)

= 0.10 * 340

=  34

​  

Out of 660 mice, 40% will be infected. The number of mice becoming infected is

N(E) = P(E) * N(S)

= 0.40 * 660

= 264

Total number of infected mice is 264 + 34 =298. Thus, the number of infected mice after two weeks is 298.

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natta225 [31]

Answer:

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Step-by-step explanation:

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If 6×10‐n= 0.06, n&gt;0, then n is
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