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Rufina [12.5K]
3 years ago
11

IF YOU HELP ME ILL GIVE YOU A MILLION BUCKS.

Mathematics
1 answer:
Len [333]3 years ago
5 0

Answer:

Here it is solved for rate:

log(1 + rate) = {log(total) -log(Principal)} ÷ Years

Let's work through your example:

log(1 + rate) = {log(6,680) -log(5,000)} / 6

log(1 + rate) = (3.8247764625 -3.6989700043) / 6

log(1 + rate) = 0.020967743

If we raise 10 to the 0.020967743 power

10^0.020967743  it produces 1 plus the rate

1 plus the rate = 10^0.020967743 = 1.0494644773

There fore the rate = .0494644773 which equals

4.94644773 per cent

Source:  https://www.1728.org/compint2.htm

Step-by-step explanation:

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