Question

Q1.

Answer 1

Answer:

5 boxes of diaries

6 boxes of pencils

10 boxes of rulers

Step-by-step explanation:

In order to find the smallest number of units that would be possible to buy, find the least common multiple between the number of units in each box:

$12\ \ 10\ \ 6\ |2\\6\ \ \ \ 5\ \ \ 3\ |2\\3\ \ \ \ 5\ \ \ 3\ |3\\1\ \ \ \ 5\ \ \ 1\ |5\\1\ \ \ \ 1\ \ \ 1\ | = 2*2*3*5=60$

The number of boxes required for each item to get 60 units is:

$d=\frac{60}{12} = 5\ boxes \\p=\frac{60}{10} = 6\ boxes \\r=\frac{60}{6} = 10\ boxes$

the smallest number of boxes of each item he could buy is:

5 boxes of diaries

6 boxes of pencils

10 boxes of rulers