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Nesterboy [21]
3 years ago
7

Resolver los problemas

Mathematics
1 answer:
Gennadij [26K]3 years ago
8 0
Your translation is "to solve or decide" hope this helps!
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How many Integers have 36 as an answer?
Maslowich
1 and 36
2 and 18
3 and 12
4 and 9
6 and 6 (this counts as one integer)

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Two groups performed an experiment separately by tossing a coin in the air. Group G performed 50 trials and group H performed 10
monitta
D. The experimental probability is closer to the theoretical probability for group H than group G.
With any experimental probability, the more trials that are done will make the experiment move more likely to be the theoretical probability. in this case, the theoretical probability for flipping a coin is 50 heads 50 tails which H is closer to. any statistical data the more data collected the more close to reality it is.
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Five hundred seventy quadrillion six hundred and thirty-three trillion nine hundred and ninety-nine billion five hundred and six
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Hello  Austint1414

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Kelly bought a new car for $20,000. The car depreciates at a rate of 10% per year. Write an equation to model the car's value.
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g A researcher wants to construct a 95% confidence interval for the proportion of children aged 8-10 living in Atlanta who own a
Helga [31]

Answer:

The sample size needed is 2401.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error of the interval is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Estimate the sample size needed if no estimate of p is available so that the confidence interval will have a margin of error of 0.02.

We have to find n, for which M = 0.02.

There is no estimate of p available, so we use \pi = 0.5

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.02 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.02\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.02}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.02})^{2}

n = 2401

The sample size needed is 2401.

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3 years ago
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