Option b), Julia's car engine overheats when the outside temperature exceeds 100 degrees is the best plausible explanation for her “check engine” light coming on while driving her car on days with temperatures over 100 degrees.
<h3>Reasoning</h3>
The other options that the engine needs to be replaced, that it cannot withstand high temperatures, or that Julia cannot drive her car on days when it is over 100 degrees outside are not plausible explanations for the situation because that is not what it indicates. the expression “check engine”
On the other hand, option b) is a plausible explanation because the light that comes on with the "Check engine" indicator is due to a temperature sensor that the engine has and that is activated once a certain temperature is exceeded.
In this case, the sensor is sensitive to a temperature differential, since it is activated when the motor compares the degrees of internal temperature with the external one.
Learn more about temperature indicators at brainly.com/question/11464844
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Mixture is the right answer
<span>Assuming that there are 36 strontium and 24 phosphate, there
aren’t any equal cations and anoins because in theory only one ionic bond is
formed by a strontium with each phosphate ion. To the point that a cation will
eventually have an excess.</span>
The molar volume of the gas : V = 447.993 L
<h3>Further explanation</h3>
Given
n = 1 mol
P = 0.05 atm
T = 273 K
Required
The molar volume
Solution
Ideal gas law :
PV=nRT
V = nRT/P
Input the value :
V = 1 x 0.08205 x 273 / 0.05
V = 447.993 L
Answer:
Activation energy of phenylalanine-proline peptide is 66 kJ/mol.
Explanation:
According to Arrhenius equation-
, where k is rate constant, A is pre-exponential factor,
is activation energy, R is gas constant and T is temperature in kelvin scale.
As A is identical for both peptide therefore-
![\frac{k_{ala-pro}}{k_{phe-pro}}=e^\frac{[E_{a}^{phe-pro}-E_{a}^{ala-pro}]}{RT}](https://tex.z-dn.net/?f=%5Cfrac%7Bk_%7Bala-pro%7D%7D%7Bk_%7Bphe-pro%7D%7D%3De%5E%5Cfrac%7B%5BE_%7Ba%7D%5E%7Bphe-pro%7D-E_%7Ba%7D%5E%7Bala-pro%7D%5D%7D%7BRT%7D)
Here
, T = 298 K , R = 8.314 J/(mol.K) and 
So, ![\frac{0.05}{0.005}=e^{\frac{[E_{a}^{phe-pro}-(60000J/mol)]}{8.314J.mol^{-1}.K^{-1}\times 298K}}](https://tex.z-dn.net/?f=%5Cfrac%7B0.05%7D%7B0.005%7D%3De%5E%7B%5Cfrac%7B%5BE_%7Ba%7D%5E%7Bphe-pro%7D-%2860000J%2Fmol%29%5D%7D%7B8.314J.mol%5E%7B-1%7D.K%5E%7B-1%7D%5Ctimes%20298K%7D%7D)
(rounded off to two significant digit)
So, activation energy of phenylalanine-proline peptide is 66 kJ/mol