Ask question

Ask question

All categories

2 years ago

13

When exchanging information with anyone involved in the collision, you should

1 answer:

postnew [5]2 years ago

7 0

Answer:

Try to be as relax as possible.
Provide names of all parties involved.
Provide vehicle information and identification details.
Provide full names, address, registration numbers and insurance company details.

Explanation:

After a collision one may be confused, afraid and have no attention about the details that what happened because all the collision event happens in a short interval of time. So the first thing one should do during information exchange is to sit back and relax and be calm so that one can remind the things at some extent. After that provide all the details about injured people and the involved vehicles.

You might be interested in

How many atoms are in 1.14 mol of sulfur trioxide

yawa3891 [41]

2.75 x 10^24

Hope this helped :)

8 0

3 years ago

I give brainliest pls help

ExtremeBDS [4]

Answer:

A

Explanation:

Radiation can come from the Sun

5 0

2 years ago

Read 2 more answers

In a chemical reaction, the mass of the products is equal to __. 11

Deffense [45]

The answer for that is 16, math right?

7 0

2 years ago

Question 1 (1 point) Which of the following summarizes cellular respiration?

salantis [7]

Answer:

oxygen reacts with glucose to produce carbon dixiode into water and release energy. It is 1

Explanation:

3 0

1 year ago

Read 2 more answers

Write the half-reactions as they occur at each electrode and the net cell reaction for this electrochemical cell containing indi

AlexFokin [52]

Explanation:

The given cell reaction is as follows.

$In(s)| In^{3+}(aq) || Cd^{2+}(aq) | Cd(s)$

Hence, reactions taking place at the cathode and anode are as follows.

At anode ; Oxidation-half reaction : $In(s) \rightarrow In^{3+}(aq) + 3e^{-}$ ...... (1)

At cathode; Reduction-half reaction : $Cd^{2+}(aq) + 2e^{-} \rightarrow Cd(s)$ ....... (2)

Hence, balance the half reactions by multiplying equation (1) by 2 and equation (2) by 3.

Therefore, net cell reaction is as follows.

$2In(s) \rightarrow 2In^{3+}(aq) + 6e^{-}$

$3Cd^{2+}(aq) + 6e^{-} \rightarrow 3Cd(s)$

Net reaction: $2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)$

Thus, we can conclude that the overall cell reaction is as follows.

$2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)$

4 0

2 years ago