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joja [24]
3 years ago
11

The width of a rectangle is five less than twice the length. What is the minimum area of the rectangle?

Mathematics
1 answer:
Andrei [34K]3 years ago
7 0
W=2L-5

-------------

A=L*W

=L(2L-5)

=2L²-5L

-------------

dA/dL=4L-5

When dA/dL=0,

4L-5=0

4L=5

L=5/4

----------------

When L=5/4

A=5/4*(2*(5/4)-5)

=5/4*(10/4-20/4)

=5/4*((-10)/4)

=5/4*(-5/2)

=-25/8

--------------------------------

*You may have been given a badly written out question. The answer doesn't make sense.

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Find the surface area of the cylinder formed by the net. Use 3.14 for π.
sineoko [7]

Answer:

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Step-by-step explanation:

The surface area of the cylinder consists of one rectangle and two circles.

1. The radius of the circle is 4 ft, then the area of the circle is

A_{circle}=\pi r^2 =\pi \cdot 4^2 =16\pi \ ft^2

2. The width of the rectangle is 1.5 ft, the length of the rectangle is the circumference of the circle.

Find the circumference:

C=2\pi r=2\pi \cdot 4=8\pi \ ft

Hence,

A_{rectangle}=1.5\cdot 8\pi =12\pi \ ft^2

3. The surface area of the cylinder is

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