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sineoko [7]
3 years ago
14

The area of a trapezoid is 243cm2. The height is 18cm and the length of one of the parallel sides is 10cm. Find the length of th

e second parallel side. Express your answer as a simplified fraction or a decimal rounded to two places.
Mathematics
1 answer:
Irina18 [472]3 years ago
8 0

Answer:

Side_2 = 17\ cm

Step-by-step explanation:

Given

Shape: Trapezoid

Area = 243cm^2

Height = 18cm

Side_1 = 10cm

Required

Determine the length of the second parallel side

The area of a trapezoid is:

Area = \frac{1}{2}(Side_1 + Side_2) * Height

Substitute values for Area, Height and Side1

243 = \frac{1}{2}(10 + Side_2) * 18

Multiply both sides by 2

2 * 243 = 2 * \frac{1}{2}(10 + Side_2) * 18

486 = (10 + Side_2) * 18

Divide both sides by 18

27 = 10 + Side_2

Side_2 = 27 - 10

Side_2 = 17\ cm

Hence;

<em>The length of the second parallel side is 17cm</em>

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Answer:

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Step-by-step explanation:

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svetlana [45]

Answer:  The required solution is

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m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.

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y(0)=-2\\\\\Rightarrow A=-2

and

y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.

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MA_775_DIABLO [31]
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In order to find the integral:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx

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