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ollegr [7]
3 years ago
12

1 + 1. . . . . . . . Free answer

Mathematics
2 answers:
Gnom [1K]3 years ago
5 0

its FISH... jk 2 LOL

WINSTONCH [101]3 years ago
4 0
2 is the answer for one plus one
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Please help Cant figure it out
IrinaVladis [17]

Answer:

C

Step-by-step explanation:

If a number is to the power of a negative number, then it is just that number's reciprocal: e.g. y⁻ˣ = \frac{1}{y^{x} }

Therefore, m⁻² will be m² in the denominator, as n⁻³ will be n³ in the numerator.

That will look like \frac{3n^{3} }{5m^{2} }.

So, that is C.

3 0
4 years ago
How do you do this?
Alenkasestr [34]

Answer:

by increasing the size ez

4 0
3 years ago
What is the first thing you need to add 1/9 + 5/6
Pavlova-9 [17]
Find the greastest common factor
7 0
3 years ago
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I NEED HELP WITH THESE TWO QUESTIONS PLZ DO NOT ANSWER IF YOU CANNOT EXPLAIN THE ANSWER
Murljashka [212]

9514 1404 393

Answer:

  1. asymptotes: x=-6, x=6, y=0; zero: x=0

  2. 20 blue fish

Step-by-step explanation:

1. The vertical asymptotes are where the denominator is zero. It factors as (x-6)(x+6), so will have zeros at x=-6 and x=6.

The horizontal asymptote is at the limit when x goes to infinity. Here, the ratio of highest-degree terms is 6/x, so the value goes to zero as x gets large.

The zero is where the numerator is zero, at x=0.

In summary:

  • vertical asymptotes: x = ±6
  • horizontal asymptote: y = 0
  • zero: (0, 0)

__

2. 60% are red, so 40% are blue. The difference in percentages is 60%-40% = 20%. The percentage of blue fish (40%) is twice the difference (=2×20%), so the number of blue fish is twice the difference in numbers.

  blue fish = 2×10 = 20 fish

<em><u>Check</u></em>

There are then 20+10=30 red fish, so 20+30=50 fish total. Reds are 30/50 = 60% of the total.

<u><em>Additional comment</em></u>

I find it often works well to work with ratios, which I can often do in my head. Other folks like to see equations. Here, we could write equations like ...

  r = 60%(r + b) . . . . reds are 60% of the total

  r - b = 10 . . . . . . . . 10 more reds than blues

We want the value of b, so we can eliminate r by substituting for it:

  r = 10 + b . . . . from the second equation above

  (10 +b) = 0.60((10 +b) + b) . . . . substitute for r

  10 +b = 6 + 1.2b . . . simplify

  4 = 0.2b . . . . subtract b+6

  20 = b . . . . . . multiply by 5 (there are 20 blue fish)

6 0
3 years ago
Factor the GCF from this polynomial <br><br> 40x-10
kipiarov [429]

10(4x-1) is the answer to your question my friend

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