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Veseljchak [2.6K]
3 years ago
9

You invested $600 in a savings account that earns simple interest. After 20 years the account had earned $720 in interest. What

was the interest rate on the account? Your answer can be in decimal or percent form.
Mathematics
1 answer:
ANEK [815]3 years ago
4 0
1% interest
Explain: in 20 years interest = $120 120 divided by 20 = 6 so u get $6 each year for $600 so therefore u would get $1 per $100
which equals 1%
hope that helps!
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NEED HELP ASAP!
ziro4ka [17]
We see it is the y terms squared so it opens left or right

in form
(y-k)^2=4(p)(x-h)
vertex is (h,k)
and p is distance from focus to vertex, also distance from vertex to directix
if p>0, then it opens to the right and dirextix is to the left of vertex
if p<0, then it opens to the left and directix is tothe right of vertex


so
(y-1)^2=4(4)(x-(-3))
vertex is (-3,1)
4>0 so dirextix is to left of vertex
left is in x direction
-3-4=-7
directix is x=-7
4 0
3 years ago
What is the sum of ​​​​​​12,837.45 and 15,910.65? Enter your answer in the box below.
Minchanka [31]

Answer: 28748.1

Step-by-step explanation:

6 0
3 years ago
What is the equation of a parabola with a directrix of y=2 and a focus point of 0,-2
KiRa [710]
Hope this helped. :)

Any point, <span><span>(<span><span>x0</span>,<span>y0</span></span>)</span><span>(<span><span>x0</span>,<span>y0</span></span>)</span></span> on the parabola satisfies the definition of parabola, so there are two distances to calculate:

<span>Distance between the point on the parabola to the focusDistance between the point on the parabola to the directrix</span>

To find the equation of the parabola, equate these two expressions and solve for <span><span>y0</span><span>y0</span></span> .

Find the equation of the parabola in the example above.

Distance between the point <span><span>(<span><span>x0</span>,<span>y0</span></span>)</span><span>(<span><span>x0</span>,<span>y0</span></span>)</span></span> and <span><span>(<span>a,b</span>)</span><span>(<span>a,b</span>)</span></span> :

<span><span><span><span><span>(<span><span>x0</span>−a</span>)</span>2</span>+<span><span>(<span><span>y0</span>−b</span>)</span>2</span></span><span>‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾</span>√</span><span><span><span>(<span><span>x0</span>−a</span>)</span>2</span>+<span><span>(<span><span>y0</span>−b</span>)</span>2</span></span></span>

Distance between point <span><span>(<span><span>x0</span>,<span>y0</span></span>)</span><span>(<span><span>x0</span>,<span>y0</span></span>)</span></span> and the line <span><span>y=c</span><span>y=c</span></span> :

<span><span><span>∣∣</span><span><span>y0</span>−c</span><span>∣∣</span></span><span>| <span><span>y0</span>−c</span> |</span></span>

(Here, the distance between the point and horizontal line is difference of their <span>yy</span> -coordinates.)

Equate the two expressions.

<span><span><span><span><span><span>(<span><span>x0</span>−a</span>)</span>2</span>+<span><span>(<span><span>y0</span>−b</span>)</span>2</span></span><span>‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾</span>√</span>=<span><span>∣∣</span><span><span>y0</span>−c</span><span>∣∣</span></span></span><span><span><span><span>(<span><span>x0</span>−a</span>)</span>2</span>+<span><span>(<span><span>y0</span>−b</span>)</span>2</span></span>=<span>| <span><span>y0</span>−c</span> |</span></span></span>

Square both sides.

<span><span><span><span>(<span><span>x0</span>−a</span>)</span>2</span>+<span><span>(<span><span>y0</span>−b</span>)</span>2</span>=<span><span>(<span><span>y0</span>−c</span>)</span>2</span></span><span><span><span>(<span><span>x0</span>−a</span>)</span>2</span>+<span><span>(<span><span>y0</span>−b</span>)</span>2</span>=<span><span>(<span><span>y0</span>−c</span>)</span>2</span></span></span>

Expand the expression in <span><span>y0</span><span>y0</span></span> on both sides and simplify.

<span><span><span><span>(<span><span>x0</span>−a</span>)</span>2</span>+<span>b2</span>−<span>c2</span>=2<span>(<span>b−c</span>)</span><span>y0</span></span><span><span><span>(<span><span>x0</span>−a</span>)</span>2</span>+<span>b2</span>−<span>c2</span>=2<span>(<span>b−c</span>)</span><span>y0</span></span></span>

This equation in <span><span>(<span><span>x0</span>,<span>y0</span></span>)</span><span>(<span><span>x0</span>,<span>y0</span></span>)</span></span> is true for all other values on the parabola and hence we can rewrite with <span><span>(<span>x,y</span>)</span><span>(<span>x,y</span>)</span></span> .

Therefore, the equation of the parabola with focus <span><span>(<span>a,b</span>)</span><span>(<span>a,b</span>)</span></span> and directrix <span><span>y=c</span><span>y=c</span></span> is

<span><span><span><span>(<span>x−a</span>)</span>2</span>+<span>b2</span>−<span>c2</span>=2<span>(<span>b−c</span>)</span>y</span></span>

3 0
3 years ago
The graph shows the water level in a bathtub, in inches, over time, t, in minutes.
vivado [14]
B. 3 to 5 & D. 7 to 12. because unchanging, in this case, means not moving.(or the flat lines)
6 0
3 years ago
Read 2 more answers
Find the quotient.
posledela
Answer :

B. 16 {a}^{2}c

step-by-step explanation :

48 {a}^{3}b{c}^{2} \div 3abc

This can be rewritten as:

\frac{ 48 {a}^{3}b {c}^{2} }{3abc}

Now,

\frac{48}{3}=16

The law of indices states that:

\frac{ {a}^{m} }{ {a}^{n} } = {a}^{m - n}

It implies that, when dividing two expressions with the same bases, repeat one of the bases and subtract the exponents.

Therefore,

\frac{ {a}^{3} }{a}= {a}^{3 - 1} = {a}^{2}

\frac{b}{b} = {b}^{1 - 1} = {b}^{0} = 1

Note: Any non-zero number exponent zero is 1

Also

\frac{ {c}^{2} }{c} = {c}^{2 - 1} = {c}^{1} = c

Hence:

\frac{ 48 {a}^{3}b {c}^{2} }{3abc} = 16 {a}^{2}c
3 0
3 years ago
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