by the double angle identity for sine. Move everything to one side and factor out the cosine term.
Now the zero product property tells us that there are two cases where this is true,
In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of
, so
where
![n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}](https://tex.z-dn.net/?f=n%5B%2Ftex%20%5Dis%20any%20integer.%5C%5CMeanwhile%2C%5C%5C%5Btex%5D10%5Csin%20x-3%3D0%5Cimplies%5Csin%20x%3D%5Cdfrac3%7B10%7D)
which occurs twice in the interval
for
and
. More generally, if you think of
as a point on the unit circle, this occurs whenever
also completes a full revolution about the origin. This means for any integer
, the general solution in this case would be
and
.
Answer:
The axis of symmetry is 
Step-by-step explanation:
we know that
In a vertical parabola, the axis of symmetry is equal to the x-coordinate of the vertex
In this problem we have a vertical parabola open upward
The x-coordinate of the vertex is equal to the midpoint between the zeros of the parabola
so
therefore
The axis of symmetry is
Answer:
???? i dont understand
Step-by-step explanation:
i think yes
Encuentra el promedio,mediana,moda y rango de los siguientes datos: 14,16,21,25,16,12,18,17,19
Doss [256]
Mean/16.75
Median/15.5
Mode/13
Range/16
