Answer:
Null hypothesis:
Alternative hypothesis:
Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%
Step-by-step explanation:
Information given
n=144 represent the random sample taken
X=81 represent the number of people with type A blood
estimated proportion of people with type A blood
is the value that we want to verify
represent the significance level
z would represent the statistic
![p_v{/tex} represent the p value Hypothesis to testWe want to test if the percentage of the population having type A blood is different from 40%.: Null hypothesis:[tex]p=0.4](https://tex.z-dn.net/?f=p_v%7B%2Ftex%7D%20represent%20the%20p%20value%20%3C%2Fp%3E%3Cp%3E%3Cstrong%3EHypothesis%20to%20test%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3EWe%20want%20to%20test%20if%20the%20percentage%20of%20the%20population%20having%20type%20A%20blood%20is%20different%20from%2040%25.%3A%20%20%3C%2Fp%3E%3Cp%3ENull%20hypothesis%3A%5Btex%5Dp%3D0.4)
Alternative hypothesis:
the statistic is given by:
(1)
Replacing the info given we got:
Now we can calculate the p value with this probability taking in count the alternative hypothesis:
Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%
Answer:
Step-by-step explanation:
Average Temperatures Suppose the temperature (degrees F) in a river at a point x meters downstream from a factory that is discharging hot water into the river is given by
T(x) = 160-0.05x^2
a. [0, 10]
For x = 0
T(0) = 160 - 0.05 × 0^2
T(0) = 160
For x = 10
T(10) = 160 - 0.05 × 10^2
T(10) = 160 - 5 = 155
The average temperature
= (160 + 155)/2 = 157.5
b. [10, 40]
For x = 10
T(10) = 160 - 0.05 × 10^2
T(10) = 160 - 5 = 155
For x = 40
T(10) = 160 - 0.05 × 40^2
T(10) = 160 - 80 = 80
The average temperature
= (80 + 155)/2 = 117.5
c. [0, 40]
For x = 0
T(0) = 160 - 0.05 × 0^2
T(0) = 160
For x = 40
T(10) = 160 - 0.05 × 40^2
T(10) = 160 - 80 = 80
The average temperature
= (160 + 80)/2 = 120
Hi there!
First, you need to find the quotient of 4 and 13, obviously.
4/13 is equal to roughly 0.308.
Those grouping symbols around it tell you that you need to find the absolute value.
Absolute value is how far away a number is from 0 on a number line. 3, for example has a absolute value of 3, and -6 has an absolute value of 6.
So, the absolute value of 4/13 is about 0.308.
Hope this helps. :)
-Spagoot
Answer:
K=-2
Step-by-step explanation:
-3 = 5k + 7
Subtract 7 to the other side
-3 -7 = 5k
-10 = 5k
-2 = k
-2/3x+3/7=1/2
-2/3x=13/14. Multiply by -2 to get positive
(-2). (-2) and whole number for x
3x=-26/14 or -13/7 [ -13/7_ 3 = -13/7 *1/3 =
Divide by 3 13/21
x=13/21
