Look at the simple circuit illustrated in the figure above. What will happen when only switch S1 is closed?
2 answers:
Answer: <u>A.</u><u> No current will flow in the circuit.</u>
Explanation:
The <em>Figure 1</em> illustrates the equivalent circuit at only switch S1 closed. That is a series circuit with two diodes, a bulb, and a battery.
Suppose that there is a current flowing in the circuit. A current flowing in the circuit implies that D1 is on. If D1 is on, there should be 0.7 V between anode and cathode (<em>see Figure 2 left</em>). However, there is not possible a low voltage on the top and a high voltage at the bottom of D1 (<em>see Figure 2 right</em>). Then, it is not viable 0.7 V between anode and cathode of diode D1. Therefore, D1 is off.
Now, we already know that this is a series circuit with the diode D1 off, so we can conclude that no current will flow in the circuit.
Correct answer is <u>A.</u><u> No current will flow in the circuit.</u>
<u />
There isn't current flowing in the circuit next the light bulb won't light up. But other things happen, for example, the high voltage goes to the light bulb at only switch S1 closed. we can say that option B. is partially wrong and options C. is wrong
Finally, there are no resistances in the circuit. So, option D. is not right
You might be interested in
Answer:
ok I've got the answer sheet on the picture I will attach
Explanation:
I had to crop to size on my computer and found them all
Answer:
I am writing a JAVA program.
public class StringMethod {
public static String longestWord(String []words) { //method that takes an array "word" of strings and returns the longest string in the array word
int pos = 0; // contains index of the longest word of array words
int longest = words[0].length(); //initially holds the length of the 1st element of words array
for(int i=1; i< words.length; i++) { // iterates through each word of the array until the end of array
if(words[i].length() > longest) { // if the length of word at i-th index of words[] is greater than the length of the word that is contained in longest variable
pos = i; // assigns the index of the longest array element to pos
longest = words[i].length(); } } //assigns the word in words[] array with the longest length to longest variable
return words[pos]; } // returns the longest string in the array
public static void main(String[] args) { //start of main() function body
String[] animals = {"cat", "horse", "elephant", "bird"}; //creates a String type array named animals which has 4 elements/words
String longest_word= longestWord(animals); //calls longestWord method to find the longest string in the array animals and assign that longest string to longest_word.
System.out.println(longest_word); }} //displays the longest word in output
Explanation:
Suppose we have the array of these elements: "cat", "horse", "elephant", "bird" These are four words in the array. Now lets see how the method longestWord() works:
int pos = 0; This variable is initialized to 0.
int longest = words[0].length();
longest holds the length of element at 0th index of words[] array. length() method is used to return the length of the first element words[0] array.
As the first element of array is "cat" so length of cat is 3. Hence longest = 3
for(int i=1; i< words.length; i++)
The loop has a variable i which is initialized to 1. The loop checks if the value of i is less than length of words[] array. The length of words array is 4 as there are 4 elements i.e. cat, horse, elephant and bird in this array. So the condition evaluates to true because i<words.length i.e. 1<4. The body of the loop will execute now. The body of loop contains an if condition if(words[i].length() > longest) which checks if the length of element of array at i-th index is greater than length of the element that is stored in longest variable. As i=1 so word[i] is word[1] which is the second element of words[] array. The second element is horse.
words[i].length() means the length of i-th element of words[] array. So this means words[1].length() i.e. the length of element of words[] at 1st index. The length of horse is 5. So the statement if(words[i].length() > longest) is true because longest=3 and words[1].length() = 5 and 5>3. So the statements of if condition will execute now.
pos = i; this variable pos is used to hold the index position of the longest element in array. So pos = 1 as longest element computed so far is "horse".
longest = words[i].length(); This statement then assigns the length of horse to longest. So now the value of longest = 5
At second iteration i is now 2. Loop condition evaluates to true because i<words.length i.e. 2<4. If condition is also true as i=2 so word[i] is word[2] which is elephant.
words[i].length() now means words[2].length() i.e. the length of element of words[] at 2nd index. The length of elephant is 8. So the statement if(words[i].length() > longest) is true because longest=5 and words[2].length() = 8 and 8>5. So the statements of if condition will execute now.
pos = i; now becomes pos = 2 as longest element computed so far is "elephant".
longest = words[i].length(); This statement then assigns the length of horse to longest. So now the value of longest = 8
At third iteration i is now 3. The loop again checks if the value of i is less than length of words[] array.The condition evaluates to true because i<words.length i.e. 3<4. The body of the loop will execute now. if(words[i].length() > longest) checks if the length of element of array at i-th index is greater than length of the element that is stored in longest variable. As i=3 so word[i] is word[3] which is the fourth element of words[] array. The fourth element is bird.
words[i].length() now means words[3].length() i.e. the length of element of words[] at 3rd index. The length of bird is 4. So the statement if(words[i].length() > longest) is false because longest=8 and words[2].length() = 4 and 4<8. So the statements of if condition will not execute now.
At fourth iteration i is now 4. The loop again checks if the value of i is less than length of words[] array.The condition evaluates to false because i==words.length i.e. 4=4. So the loop breaks.
return words[pos]; statement returns the index position of longest word in words[] array. pos = 2 So the array element at 2nd index is basically the third element of array words[] i.e. elephant. So the longest string in the array is elephant.
