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EastWind [94]
3 years ago
7

A triangle has vertices at the points (1,2) (4,6) and (4,-1) what is the approximate perimeter of the triangle

Mathematics
1 answer:
Nuetrik [128]3 years ago
6 0
approximately it's perimeter is 16 units.
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A, radius is half of the diameter. Which would be half the length of circle

4 0
3 years ago
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Instructions: Rewrite the equation in Slope-Intercept Form. y−2=−2/5(x−5)
Leno4ka [110]

The equation in Slope-Intercept Form is y = -2/5 x + 4.

We have given that,

y−2=−2/5(x−5)

We have to rewrite the equation in Slope-Intercept Form.

<h3>What is the slope-intercept form of the line?</h3>

slope-intercept form is y = mx + b

for equation y - 2 = -2/5 (x - 5) we need to simplify/rearrange

so y - 2 = -2/5 x + -2/5 (-5)

= -2/5 x + 2

=> y = -2/5 x + 4

This line has a gradient of -2/5 (goes down 2 units and across 5 units) and a y-intercept of 4 so passes through the point (0,4).

To learn more about the line visit:

brainly.com/question/657646

#SPJ1

4 0
2 years ago
Which of the following is a like radical to 3x square root 5?
Airida [17]
Pretty sure it’s D good luck
8 0
3 years ago
Add (3+2i)+(-5+6i)<br> A) -8+8i<br> B) -8-4i<br> C) -2+8i<br> D) -2+4i
balandron [24]
The answer it b your welcome
6 0
3 years ago
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From a radar station, the angle of elevation of an approaching airplane is 32.5 degree. The horizontal distance between the plan
denis23 [38]

Answer: 42.21 km

Step-by-step explanation:

We can solve this using trigonometry, since we have the following data:

\theta=32.5\° is the the angle of elevation

d=35.6 km is the horizontal distance between the plane and the radar station

x is the hypotenuse of the right triangle formed between the radar station and the airplane

Now, the trigonometric function that will be used is <u>cosine</u>:

cos\theta=\frac{d}{x} because d is the adjacent side of the right triangle

cos(32.5\°)=\frac{35.6 km}{x}

Finding x:

x=\frac{35.6 km}{cos(32.5\°)}

x=42.21 km

4 0
3 years ago
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