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Sladkaya [172]
3 years ago
5

Identify the type of observational study​ (cross-sectional, retrospective, or​ prospective) described below. A research company

uses a device to record the viewing habits of about 25002500 ​households, and the data collected todaytoday will be used to determinenbsp the proportion of households tuned to a particular newsnews program.. Which type of observational study is described in the problem​ statement?
Mathematics
1 answer:
shepuryov [24]3 years ago
7 0

Answer:

Cross Sectional

Step-by-step explanation:

A cross sectional is one in which an association is developed between a risk factor or an outcome.

In the given question the device is used to record the viewing habits of about 2500 ​households, and the data collected today will be used to determine  the proportion of households tuned to a particular news program. There will be risk factor in today's research with the future developed program which will the outcome.

For example there are 20 students in my class who cannot write. So I develop a program to help them write. But the next year there may not be any student who would require such help.So there's a risk factor associated with the outcome.

Cross sectional results are recorded in a two ways table showing do's and don'ts.

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Step-by-step explanation:

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bija089 [108]
Y intercept is -6

Y= 5x^2-X-6
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4 years ago
HELP 100 POINTS The population of a city is modeled with the function P=250,000e^0.013t​, where t is the number of years since 2
erma4kov [3.2K]
Pretty difficult problem, but that’s why I’m here.
First we need to identify what we’re looking for, which is t. So now plug 450k into equation and solve for t.
450000 = 250000e^0.013t
Now to solve this, we need to remember this rule: if you take natural log of e you can remove x from exponent. And natural log of e is 1.
Basically ln(e^x) = xln(e) = 1*x
So knowing this first we need to isolate e
450000/250000 = e^0.013t
1.8 = e^0.013t
Now take natural log of both
Ln(1.8) = ln(e^0.013t)
Ln(1.8) = 0.013t*ln(e)
Ln(1.8) = 0.013t * 1
Now solve for t
Ln(1.8)/0.013 = t
T= 45.21435 years
Now just to check our work plug that into original equation which we get:
449999.94 which is basically 500k (just with an error caused by lack of decimals)
So our final solution will be in the 45th year after about 2 and a half months it will reach 450k people.
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2 years ago
Autumn buys eggs and apples at the store.
soldier1979 [14.2K]

Answer:

\frac{(5.76-34.14)}{6}

Step-by-step explanation:

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