A) The coordinates of R is (-8,9)
B) The length of RS to the nearest tenth of a unit is 17.9
Greetings!
The best way to compare fractions is to find the LCM (The Lowest Common Denominator) of each of the fractions. This can be done simply by listing the multiples of the denominators.
Multiples:
3: 3,6,9,12,15,18,21,24,27...210,213
10:10,20,30,40,60,70,80...210,220
6: 6,12,18,24,30,36,42,48...210,216
7: 7,14,21,28,35,42,49...210,217
The LCM is 210:
3*70=210
10*21=210
6*35=210
7*30=210
Now, we must do what we do the denominators to the numerators:
1*70=70
70/210
2*21=42
42/210
1*35=35
=35/210
2*30=60
=60/210
The fraction with the largest numerator has the greatest value; In this case it 1/3 or 70/210.
Hope this helps.
-Benjamin
I’m pretty sure you can make four if you’re distributing them evenly because they can both be decided by four so each kit would get 5 water bottles and 3 cans. I’m not 100% sure but lmk if it helped :)
Answer:
a) The 95% of confidence intervals for the average spending
(23.872 , 32.128)
b) The calculated value t= 1< 1.711( single tailed test) at 0.05 level of significance with 24 degrees of freedom.
The null hypothesis is accepted
A survey of 25 young professionals statistically that the population mean is less than $30
<u>Step-by-step explanation</u>:
Step:-(i)
Given data a survey of 25 young professionals fond that they spend an average of $28 when dining out, with a standard deviation of $10
The sample size 'n' = 25
The mean of the sample x⁻ = $28
The standard deviation of the sample (S) = $10.
Level of significance ∝=0.05
The degrees of freedom γ =n-1 =25-1=24
tabulated value t₀.₀₅ = 2.064
<u>Step 2:-</u>
The 95% of confidence intervals for the average spending
(

( 28 - 4.128 , 28 + 4.128)
(23.872 , 32.128)
a) The 95% of confidence intervals for the average spending
(23.872 , 32.128)
b)
Null hypothesis: H₀:μ<30
Alternative Hypothesis: H₁: μ>30
level of significance ∝ = 0.05
The test statistic


t = |-1|
The calculated value t= 1< 1.711( single tailed test) at 0.05 level of significance with 24 degrees of freedom.
The null hypothesis is accepted
<u>Conclusion</u>:-
The null hypothesis is accepted
A survey of 25 young professionals statistically that the population mean is less than $30