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Snowcat [4.5K]
3 years ago
13

How can i do this excercise?

Mathematics
1 answer:
Deffense [45]3 years ago
4 0
Make it less blurry the picture so I can solve
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Simplify: 9‾√−4‾√<br><br> −1<br><br> 1<br><br> 5‾√<br><br> 7‾√
11111nata11111 [884]

Answer:

ddddddhnm.,mnbvcx

Step-by-step explanation:

xfdtbujnj

8 0
3 years ago
Find 60% of 264<br><br><br> Explain<br><br> Numbers that could be the answer 46, 27, 51, 16.1
babunello [35]

Answer:

44

Step-by-step explanation:

divide 60÷264 will give u 44

8 0
4 years ago
5x-12=42<br><br> A.7<br> B.8<br> C.9<br> D.6
Mashutka [201]

Answer:

D.6

Step-by-step explanation:

5 0
4 years ago
Figure R was rotated about the origin (0,0) by 270, degrees clockwise Which figure is the image of R? Choose 1 answer:
sasho [114]

Answer: Look that is not of mi grade!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! sorry baby XD ),:

Step-by-step explanation:

7 0
3 years ago
Với điều kiện nào của m thì phương trình ( 3m^2 - 4) x -1=m-x có nghiệm duy nhất?
Shtirlitz [24]
 <span>a, để pt có nghiệm thì denta ≥ 0 <=> (3-m)^2 - 4( 3-2m) ≥ 0 <=> m^2 +2m-3 ≥ 0 ( ^ là mũ) 
giải bpt mới tìm được đó ta đc : m ≤ -3 hoặc m ≥ 1 
b, * Xét m-1=0 <=> m=1 => thay m=1 vào pt thì pt có 1 nghiệm là 1/8 (1) 
* Xét m-1 ≠ 0 <=> m ≠ 1 
=> pt có nghiệm khi denta' ≥ <=> (m+3)^2 - (m-1)(-m+2) ≥0 <=> 2m^2 +3m+11 ≥ 0 (*) 
-> bpt (*) có denta < 0 nên nó luôn đúng với mọi m ≠1 -> denta của pt đã cho luôn > 0 với mọi m ≠ 1 (2) 
từ (1) (2) => với mọi m pt luôn có nghiệm </span>
6 0
3 years ago
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