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Maru [420]
3 years ago
14

(x+4)(x+3)-x(x-2)=48

Mathematics
1 answer:
nikitadnepr [17]3 years ago
8 0

Step-by-step explanation:

trust me its b i got it right

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Find the range of F<img src="https://tex.z-dn.net/?f=f%28x%29%3D%20%5Cfrac%7B2%7D%7Bx-7%7D%20" id="TexFormula1" title="f(x)= \fr
steposvetlana [31]
Answer: y \in R; y \neq 0
Explanation: For this, it is often best to find the horizontal asymptote, and then take limits as x approaches the vertical asymptote and the end behaviours.

Well, we know there will be a horizontal asymptote at y = 0, because as x approaches infinite and negative infinite, the graph will shrink down closer and closer to 0, but never touch it. We call this a horizontal asymptote.
So we know that there is a restriction on the y-axis.

Now, since we know the end behaviours, let's find the asymptotic behaviours.

As x  approaches the asymptote of 7⁻, then y would be diverging out to negative infinite.
As x approaches the asymptote at 7⁺, then y would be diverging out to negative infinite.

So, our range would be: y \in R; y \neq 0
6 0
3 years ago
(-6)(4) preform indicated operation
Tems11 [23]

Answer:

-24

Step-by-step explanation:

(-6)(4)

The indicated operation is multiplication

-24

5 0
3 years ago
Read 2 more answers
5<br> Find x to the nearest tenth.<br> 18.7<br> 13<br> 19.3<br> NEXT QUESTION<br> © ASK FOR HELP
Iteru [2.4K]
Think it’s option 1.3
6 0
3 years ago
The sum of the squares of 3 consecutive positive integers is 116. What are the numbers?
irina [24]
1st number = n
2nd number = n+1
3rd number = n+2

sum of the squares of 3 consecutive numbers is 116

n² + (n+1)² + (n+2)² = 116
n² + (n+1)(n+1) + (n+2)(n+2) = 116
n² + [n(n+1)+1(n+1)] + [n(n+2)+2(n+2)] = 116
n² + n² + n + n + 1 + n² + 2n + 2n + 4 = 116
n² + n² + n² + n + n + 2n + 2n + 1 + 4 = 116
3n² + 6n + 5 = 116  Last option.

5 0
3 years ago
I don’t understand the question and I can’t find anything in my notes to help
lara [203]

Step-by-step explanation:

The problem states that you have a linear function so expect your equation to have this form:

y = mx + b

where m is the slope and b is the y-intercept. You are also given two points: P1(5, 6) and P2(14, 60). Use these points to solve for the slope m.

m = (y2 - y1) / (x2 - x1) = (60 - 6)/(14 - 5)

= 54/9 = 6

So our equation now becomes

y = 6m + b

To solve for b, plug in the values of P1:

6 = 6(5) + b ---> b = -24

Therefore, our equation is

y = 6m - 24

The rest of the points are

(8, 24)

(11, 42)

7 0
3 years ago
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