A.) R(20) = -10(20)^2 + 800(20) = -10(400) + 16000 = -4000 + 16000 = $12,000
R(25) = -10(25)^2 + 800(25) = -10(625) + 20000 = -6250 + 20000 = $13,750
R(30) = -10(30)^2 + 800(30) = -10(900) + 24000 = -9000 + 24000 = $15,000
b.) For maximum revenue, dR/dp = 0
dR/dp = -20p + 800 = 0
20p = 800
p = 40
Therefore, the maximum revenue will be recorded when the price is set at $40.
The quadratic formula is above.
You want each equation in standard form: ax^2 + bx + c = 0
I begin each problem by defining variables.
For instance 3. Is in standard form. X^2 -2x - 3 = 0. a = 1, b = -2, c = -3
Now use quadratic formula: x = [- b + or - sqrt(b^2 - 4ac)]\2a
Answer:
$6.96
Step-by-step explanation:
(4*8.99) + (3*7)
35.96 + 21 = 56.96
50- 56.96 = -6.96 So she owes 6.96
Answer:
y= 1 1/2
Step-by-step explanation:
A. f(x)=ln(x+4)-5
If it shifts to the left side then in braces put a (+) sign and if it shifts to the right then in braces put a (-) sign. If it goes up it’s positive and if it goes down it’s negative