A blind taste test is over and a new favorite juice flavor has been selected. The new flavor received 4

Replace 27 out of 45 desks. What percent of the desks need to be replaced?

Volgvan

I believe the answer is 40%. I hope this helps!

8 0

3 years ago

Three friends collected aluminum cans from the neighborhood to recycle in total they receive 300 cans many collected 90 Jim coll

spin [16.1K]

Given

Total cans = 300

Manny= 90

Jim =100

Bob=110

Now their percentage

Manny percentage

$\begin{gathered} manny=\frac{90}{300}\times100\text{ \%} \\ \\ Manny\text{ percentage=}\frac{90}{3}\text{ \%} \\ \\ Manny\text{ percentage =30 \%} \end{gathered}$

Jim Percentage

$\begin{gathered} Jim=\frac{100}{300}\times100\text{ \%} \\ Jim\text{ percentage=}\frac{1}{3}\times100\text{ \%} \\ Jim\text{ percentage=33.333\%} \end{gathered}$

Bob percentage

$undefined$

6 0

1 year ago

How do you do this question?

Ksivusya [100]

Answer:

V = (About) 22.2, Graph = First graph/Graph in the attachment

Step-by-step explanation:

Remember that in all these cases, we have a specified method to use, the washer method, disk method, and the cylindrical shell method. Keep in mind that the washer and disk method are one in the same, but I feel that the disk method is better as it avoids splitting the integral into two, and rewriting the curves. Here we will go with the disk method.

$\mathrm{V\:=\:\pi \int _a^b\left(r\right)^2dy\:},\\\mathrm{V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy}$

The plus 1 in '1 + 2/x' is shifting this graph up from where it is rotating, but the negative 1 is subtracting the area between the y-axis and the shaded region, so that when it's flipped around, it becomes a washer.

$V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=\pi \cdot \int _1^3\left(1+\frac{2}{y}\right)^2-1dy\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\= \pi \left(\int _1^3\left(1+\frac{2}{y}\right)^2dy-\int _1^31dy\right)\\\\$

$\int _1^3\left(1+\frac{2}{y}\right)^2dy=4\ln \left(3\right)+\frac{14}{3}, \int _1^31dy=2\\\\=> \pi \left(4\ln \left(3\right)+\frac{14}{3}-2\right)\\=> \pi \left(4\ln \left(3\right)+\frac{8}{3}\right)$

Our exact solution will be V = π(4In(3) + 8/3). In decimal form it will be about 22.2 however. Try both solution if you like, but it would be better to use 22.2. Your graph will just be a plot under the curve y = 2/x, the first graph.

5 0

3 years ago

Solve for the value of s

Temka [501]

Answer:

15

Step-by-step explanation:

9 times 15+8+37=180

180 is a full line

7 0

2 years ago

Read 2 more answers

A boy of 30 kg is carrying a load of 20 kg to the top of a building of height 13m . Find his total work done . If he can do it i

r-ruslan [8.4K]

Step-by-step explanation:

g of load= 30 kg ( kilogram)

load at top of building=20 kg( kilogram)

building height=13 m(meter)

<h2>or"= total work done=?</h2>

<h3> or"=. power developed by him= ? </h3>

now ,

30*20*13÷20

again ,30*20*13

________

20

answer,= 390

5 0

3 years ago