F’(x)= -akxsinkx
F’’(x)= -a(kx)^2coskx
I’m really sorry if the answer turned out wrong but I tried my best!
round your answer to the nearest hundredth place the answer is a
Answer:
- 6 2/3 qt 80%
- 13 1/3 qt 20%
Step-by-step explanation:
It is often convenient to solve a mixture problem by letting a variable represent the quantity of the higher-concentration contributor to the mix.
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We can let x represent the number of quarts of 80% solution needed. Then (20-x) is the number of quarts of 20% solution needed. The amount of salt in the final mix is ...
0.80x +0.20(20-x) = 0.40(20)
0.60x = 0.20(20) . . . . . . . . subtract 0.20(20) and simplify
x = 20/3 = 6 2/3 . . . . . . . . . divide by 0.60; quarts of 80% solution
(20 -x) = 13 1/3 . . . . . . . . . . amount of 20% solution needed
The teacher should mix 6 2/3 quarts of 80% solution with 13 1/3 quarts of 20% solution.
7/8 + 3/6
= 10/14
= 5/7
= 0.71
And if you want to make it a whole number, you multiply by 100 and you should get 71 as a whole number. Therefore: he can pour 71 gallon servings of bottled water. I hope this is helpful!!^_^!!
answer: it would be one solution, becasue the variables are different and the constants dont matter, since the variables are different
