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3 years ago

What is 9/21 in simplest form

Mathematics

2 answers:

andriy [413]3 years ago

4 0

You divide a by 3, and then you will get 3/7.

telo118 [61]3 years ago

3 0

You divide 9 and 21 by 3, then you get 3/7. :D

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In ΔXYZ, z = 81 cm, ∠Y=139° and ∠Z=6°. Find the length of y, to the nearest 10th of a centimeter.

Delicious77 [7]

Answer:

508.4

Step-by-step explanation:

This is on delta math

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match the linear equations with their x-

jolli1 [7]

Answer:

Part 1) $x-2y=2$ ----> (2,0) and (0,-1)

Part 2) $-3x+3y=7$ ----> (-7/3,0) and (0,7/3)

Part 3) $7x-y=21$ ----> (3,0) and (0,-21)

Part 4) $3x-5y=-20$ ----> (-20/3,0) and (0,4)

Step-by-step explanation:

we know that

The y-intercept is the value of y when the value of x is equal to zero

The x-intercept is the value of x when the value of y is equal to zero

Part 1) we have

$x-2y=2$

1) Find the x-intercept

For y=0

$x-2(0)=2\\x=2$

the x-intercept is (2,0)

2) Find the y-intercept

For x=0

$0-2y=2\\y=-1$

the y-intercept is (0,-1)

Part 2) we have

$-3x+3y=7$

1) Find the x-intercept

For y=0

$-3x+3(0)=7\\x=-\frac{7}{3}$

the x-intercept is (-7/3,0)

2) Find the y-intercept

For x=0

$-3(0)+3y=7\\y=\frac{7}{3}$

the y-intercept is (0,7/3)

Part 3) we have

$7x-y=21$

1) Find the x-intercept

For y=0

$7x-(0)=21\\x=3$

the x-intercept is (3,0)

2) Find the y-intercept

For x=0

$7(0)-y=21\\y=-21$

the y-intercept is (0,-21)

Part 4) we have

$3x-5y=-20$

1) Find the x-intercept

For y=0

$3x-5(0)=-20\\x=-\frac{20}{3}$

the x-intercept is (-20/3,0)

2) Find the y-intercept

For x=0

$3(0)-5y=-20\\y=4$

the y-intercept is (0,4)

8 0

3 years ago

Find the missing value in the picture?

Angelina_Jolie [31]

Answer:

AC=13.6

Step-by-step explanation:

let the triangle is ABC

radius =6 , diameter =6*2=12

therefore AB=12

since BC is a tangent

therefore angle B =90 degrees

BC=6.4

$\sqrt (AB)^2+(BC)^2 =AC$

AC=13.6

5 0

3 years ago

in a plantation,there are 230 trees in a row. There are at least 3 papaya trees between any 2 rambutan trees. What is the larges

Zinaida [17]

Answer:

Step-by-step explanation:

The total number of trees in a row that starts and ends with a rambutan tree is ...

4n -3 . . . . for n rambutan trees

So, the number of rambutan trees that there can be in a row of 230 trees is ...

4n -3 ≤ 230

4n ≤ 233

n ≤ 233/4 = 58 1/4

The largest possible number of rambutan trees in a row of 230 trees is 58.

_____

1 rambutan tree: R . . . n=1, tree count = 1

2 rambutan trees: RpppR . . . n=2, tree count = 5

3 rambutan trees: RpppRpppR . . . n=3, tree count = 9

The tree count is an arithmetic sequence with first term 1 and common difference 4. Then the n-th term of the sequence is ...

tn = a1 +d(n -1) = 1 +4(n -1) = 4n -3

Term 58 is ...

t58 = 4·58 -3 = 229

So, the row of trees might be ...

RpppRppp ... RpppRpppRp . . . . with 58 R and 172 p.

7 0

3 years ago