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viva [34]
3 years ago
14

A rectangular piece of land has an area of 3/4 square mile. The land is 21/2 mile. What is its width

Mathematics
1 answer:
OleMash [197]3 years ago
4 0

Answer:

The width of the rectangle is  \frac{1}{14} miles

Step-by-step explanation:

Given as for rectangle

The area of rectangle = A = \frac{3}{4} mile²

The Length of rectangle = L = \frac{21}{2} mile

Let The width of rectangle = W miles

Now, From area of rectangle

I.e Area of Rectangle = Length × Width

Or , A = \frac{21}{2} mile  × W mile

Or, \frac{3}{4} mile² = \frac{21}{2} mile  × W mile

or, W = \frac{\frac{3}{4}}{\frac{21}{2}} mile

or, W = \frac{3\times 2}{4\times 21}

∴  W = \frac{1}{14} miles

Hence The width of the rectangle is  \frac{1}{14} miles  Answer

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The local ice cream shop offers 3 different types of cones and 15 different flavors of ice cream. How many possible ice cream co
oksian1 [2.3K]

Answer:

45

Step-by-step explanation:

There are 3 cones and 15 flavors

Multiply the number of cones by the number of flavors

3*15

45

There are 45 possible combinations

5 0
3 years ago
It has been estimated that 40% of marriages end in divorce. If you randomly select 9 recently married couples what is the probab
Serga [27]

Answer:

Step-by-step explanation:

Hello!

In this example you are interested to know how many matrimonies and up in divorce.

The study variable is X: number of marriages that ended up in divorce in a sample of nine.

This variable is a discrete variable and a quick check will tell you if it follows the binomial criteria, if it does, then the variable will have binomial distribution:

Binomial criteria:

1. The number of observation of the trial is fixed (n = 9)

2. Each observation in the trial is independent, this means that none of the trials will affect the probability of the next trial.

3. The probability of success in the same from one trial to another (the "success" of the trial is that the matrimony ended up in divorce and it's estimated probability is p=0.40

So X≈ Bi (n;ρ)

You have to calculate the probability that at least one of the marriages end in divorce, this is that "one or more" of the marriages end in divorce, symbolically:

P(X≥1)

This expression includes the probabilities P(X=1), P(X=2), P(X=3), P(X=4), P(X=5), P(X=6), P(X=7), P(X=8), P(X=9).

One way to calculate this is by applying the formula for calculating point probabilities under the binomial distribution P(X)= \frac{n!}{(n-X)!X1}*(p^X)*(q^n-X) nine times and then add them or you can use a table of the binomial distribution. These tables show cumulative probabilities for many distributions, P(X≤x₀)

To reach the probability value using the table you have to do the following:

P(X≥1)= 1 - P(X<1)

One is the max cumulative probability, so you have to subtract from it everything that isn't included in the expression, the only probability that is "left out" from P(X≥1) is P(X=0), in the table you have to look for the probability of P(X≤0)= 0.0101, then you calculate the probability as follow:

P(X≥1)= 1 - P(X<1)= 1 - P(X≤0)= 1 - 0.0101= 0.9899

I hope this helps!

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Answer:

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Answer:

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Step-by-step explanation:

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