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3 years ago

How is an inversely proportional relationship different from a directly proportional relationship?

1 answer:

4 0

Directly proportional: as one amount increases,
another amount increases at the same rate.

Inversely Proportional: when one value decreases at the same rate that the other increases.

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Dream borrowed $500 at an interest rate of 8%. At the end of the loan period, she had to pay back $530. How long was the loan fo

Aliun [14]

Answer:

The loan was for 9 months only

Step-by-step explanation:

In this question, we are concerned with calculating the time taken for a loan om an interest to be paid back

To calculate this, we use the simple interest formula

Mathematically;

I = PRT/100

where P is the principal which is the amount borrowed and that is $500 according to the question

R is the rate which is 8% according to the question

Interest can be calculated by subtracting the principal from the amount paid back = 530-500 = 30$

We now plug these values into the equation

30 = (500 × 8× T)/100

100 × 30 = 4000T

T = 3000/4000

T = 0.75 (same as 0.75 × 12 months = 9 months)

5 0

3 years ago

What is 6 3/4 x 3/5 A) 54/20 B) 75/12 C) 81/20 D) 9/4

steposvetlana [31]

The answer you are looking for is C my friend

8 0

3 years ago

Pls helpppp meeeee I don’t know

o-na [289]

Answer:

2y = x+6 is the answer

please mark brainiest

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Line A has an equation of y=-2/5x + 3. What is the slope of a line perpendicular

Nat2105 [25]

Answer:

$\frac{5}{2}$

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - $\frac{2}{5}$ x + 3 ← is in slope- intercept form

with slope m = - $\frac{2}{5}$

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-\frac{2}{5} }$ = $\frac{5}{2}$

5 0

3 years ago

I need to find the surface area and volume of all three figures. If you could provide what equations you used to I will be grate

Margarita [4]

Answer:

Part 1) Sphere The surface area is equal to $SA=196\pi\ m^{2}$ and the volume is equal to $V=\frac{1,372}{3}\pi\ m^{3}$

Part 2) Cone The surface area is equal to $SA=(16+4\sqrt{65})\pi\ units^{2}$ and the volume is equal to $V=\frac{112}{3}\pi\ units^{3}$

Part 3) Triangular Prism The surface area is equal to $SA=51.57\ mm^{2}$ and the volume is equal to $V=17.388\ mm^{3}$

Step-by-step explanation:

Part 1) The figure is a sphere

a) Find the surface area

The surface area of the sphere is equal to

$SA=4\pi r^{2}$

we have

$r=14/2=7\ m$ ----> the radius is half the diameter

substitute

$SA=4\pi (7)^{2}$

$SA=196\pi\ m^{2}$

b) Find the volume

The volume of the sphere is equal to

$V=\frac{4}{3}\pi r^{3}$

we have

$r=14/2=7\ m$ ----> the radius is half the diameter

substitute

$V=\frac{4}{3}\pi (7)^{3}$

$V=\frac{1,372}{3}\pi\ m^{3}$

Part 2) The figure is a cone

a) Find the surface area

The surface area of a cone is equal to

$SA=\pi r^{2} +\pi rl$

we have

$r=4\ units$

$h=7\ units$

Applying Pythagoras Theorem find the value of l (slant height)

$l^{2}=r^{2} +h^{2}$

substitute the values

$l^{2}=4^{2} +7^{2}$

$l^{2}=65$

$l=\sqrt{65}\ units$

$SA=\pi (4)^{2} +\pi (4)(\sqrt{65})$

$SA=16\pi +4\sqrt{65}\pi$

$SA=(16+4\sqrt{65})\pi\ units^{2}$

b) Find the volume

The volume of a cone is equal to

$V=\frac{1}{3}\pi r^{2}h$

we have

$r=4\ units$

$h=7\ units$

substitute

$V=\frac{1}{3}\pi (4)^{2}(7)$

$V=\frac{112}{3}\pi\ units^{3}$

Part 3) The figure is a triangular prism

a) The surface area of the triangular prism is equal to

$SA=2B+PL$

where

B is the area of the triangular base

P is the perimeter of the triangular base

L is the length of the prism

Find the area of the base B

$B=\frac{1}{2} (2.7)(2.3)=3.105\ mm^{2}$

Find the perimeter of the base P

$P=2.7*3=8.1\ mm$

we have

$L=5.6\ mm$

substitute the values

$SA=2(3.105)+(8.1)(5.6)=51.57\ mm^{2}$

b) Find the volume

The volume of the triangular prism is equal to

$V=BL$

where

B is the area of the triangular base

L is the length of the prism

we have

$B=3.105\ mm^{2}$

$L=5.6\ mm$

substitute

$V=(3.105)(5.6)=17.388\ mm^{3}$

5 0

3 years ago