A random survey was taken in Centerville. People in twenty-five homes were asked how many cars were registered to their househol
d. The results are shown in the list below. 1, 2, 1, 0, 3, 4, 0, 1, 1, 1, 2, 2, 3, 2, 3, 2, 1, 4, 0, 0, 2, 2, 1, 1, 1 What is the mean, median, and mode of the Centerville data? a. 1.6, 1, 1 c. 1, 1, 1 b. 1.6, 2, 1 d. 2, 2, 2
In order to find the mean, you first count how many numbers are there. Then, you add all numbers together and divide them by the total of numbers. In this case, you would add (1+2+1+0+3+4+0+1+1+1+2+2+3+2+3+2+1+4+0+0+2+2+1+1+1), which equals to 40. The total of numbers is 25. You divide 40 by 25, and it would get you 1.6. Therefore, your mean is 1.6.
To calculate the median, you list the numbers from least to greatest, and find the middle number. The list for this survey would be 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4. The middle number of this list is 1, therefore, your median is 1.
The mode is simply the number that appears the most in this list. There are 4 zeroes, 9 ones, 7 twos, 3 threes, and 2 fours. The most in this list would be 1, because there are 9 of them. Your mode is 1.
The answer, at least what I got, is 17.375 . They'd have to open an eighteenth package because the extra .375 is not in the original package, so I would go with B .
