<span>At 8in to 250 feet the skyscraper converts to the following.
1.6 in/8 in x 250ft = 50 ft long
2.8in/8in x 250ft = 87.5 ft wide
11.2in/8in x 250ft = 350 ft high
You get this because every 8 in is 250 feet so you need to calculate the ratio of scale to that 8in per 250 feet.</span>
Answer:
1/16
Step-by-step explanation:
4^-2 is the same as 1/4^2
and then calculate 4^2 to get 16, making it 1/16.
The distance depends on the time.
So now we need to find the constant of variation or the constant of proportionality.
To do so we must find y(the dependent variable) and x(the independent variable).
To find the constant(k) we must find y/x
Since y/x=k
Then 2.25/.75=k
k=3
None of the above.
The orthocenter is the point where the three altitudes meet. An altitude is the line from one vertex perpendicular to the opposite side.
Answer:
Check Explanation
Step-by-step explanation:
The map isn't available, but, one can draw this bearings with the descriptions given
Angles for bearings are usually drawn, reading from the north direction.
A sketch of the described bearings and locations of the stadium, university and the hospital is presented in the attached image to this question.
For the sketch on the map.
On The map, draw a four-cardinal points' cross at the stadium draw a line from the bearing 050° from the stadium's four cardinal points' cross. Leave the line as it is.
Then, draw another four cardinal points' cross at the hospital and draw a line from the bearing 300° from the hospital's four cardinal points' cross.
Wherever the line from the hospital meets the line from the stadium, is where the University is located.
Hope this Helps!!!!