Answer:
149°
Step-by-step explanation:
The sum of two interior angles in a triangle is equal to an exterior angle that's supplementary to the third interior angle
<FRO + <RFO = <FOG
60° + 86 = 146
To be precise, the size of your sample space is <span><span>(<span>2410</span>)</span><span>(<span>2410</span>)</span></span>. This number does go on the bottom of the fraction, and what goes on top is the size of the event. Break up the event into independent events 1. choose the 2 defective bulbs, and 2. choose the remaining 8 bulbs. I don't have much choice in event 1. There is only one way to choose both of the defective balls. In other words, <span><span>(<span>22</span>)</span><span>(<span>22</span>)</span></span> (choosing 2 defective bulbs from a set of 2 defective bulbs). For event 2, there are <span><span>24−2=22</span><span>24−2=22</span></span> nondefective bulbs, and I must choose <span>88</span> of them, so that's <span><span>(<span>228</span>)</span><span>(<span>228</span>)</span></span>. Finally, since events 1 and 2 are independent, we multiply the answers for the combined event: <span><span><span>(<span>22</span>)</span><span>(<span>228</span>)</span></span><span><span>(<span>22</span>)</span><span>(<span>228</span>)</span></span></span>
<span><span>P=<span><span><span>(<span>22</span>)</span><span>(<span>228</span>)</span></span><span>(<span>2410</span>)</span></span></span><span>P=<span><span><span>(<span>22</span>)</span><span>(<span>228</span>)</span></span><span>(<span>2410</span>)</span></span></span></span>
Or, since <span><span><span>(<span>22</span>)</span>=1</span><span><span>(<span>22</span>)</span>=1</span></span>,
<span><span>P=<span><span>(<span>228</span>)</span><span>(<span>2410</span>)</span></span></span><span>P=<span><span>(<span>228</span>)</span><span>(<span>2410</span>)</span></span></span></span>
Hope this helps!
Answer:
15p+15
Step-by-step explanation:
3(3p+5)-6p+3p(5-1)
9p+15-6p+3p(4)
9p-6p+15+12p
3p+12p+15
15p+15
Answer:
Step-by-step explanation:
Given the circumference of Circle K = π
circumference of Circle L = 4π
Ratio of their circumferences = Ck/Cl
Ratio of their circumferences = π/4π
Ratio of their circumferences = 1/4 = 1:4
For their radii
C = 2πr
for circle k with circumference π
π = 2πrk
1 = 2rk
rk = 1/2
for circle l with circumference 4π
4π = 2πr
4 = 2r
r = 4/2
rl = 2
ratio
rk/rl = 1/2/2
rk/rl = 1/4 = 1:4
for the areas
Area of a circle = πr²
for circle k
Ak = π(1/2)²
Ak = π(1/4)
Ak = π/4
for circle l
Al = π(2)²
Al = 4π
Ratio of their areas
Ak/Al = π/4/(4π)
Ak/Al = π/16π
Ak/Al = 1/16 = 1:16
