Can you help me with these?

Write: y - 6 = -12(x+4) in slope intercept form-

Artist 52 [7]

Answer:

y= -12x - 42

Step-by-step explanation:

slope intercept form is y=mx +b

y-6 = -12(x+4) simplify

y - 6 = -12x - 48 separate y by adding 6 to both sides of the equation

y = -12x - 42

7 0

3 years ago

Describe the rule for the sequence. 3,5, 8, 13, 21, 34, ...

andrezito [222]

Add 2 to 3 and get 5 add 3 and get 8 add 5 to get 13 add 8 to get 21

4 0

3 years ago

Help needed! Thank you!

Gelneren [198K]

Answer:

C but see below.

Step-by-step explanation:

If I'm reading this correctly, you mean 31/24. It really can't be much else. The sine and cosine are both incorrect because both involve the hypotenuse which must be calculated in order for them to be considered. In addition 31/24 is greater than one which is impossible for both the Sine and the Cosine.

That leaves K and D

Tan(D) = 24/31 which is not an option.

That leaves C.

tan(K) = 31/24 which is what you have to choose. If your choice is not written this way, then there is no answer.

3 0

3 years ago

Daniel created an intersection with his race track. One of the angles at the intersection is 55°. What are the three other angle

melomori [17]

Answer:

55, 125 and 125

Step-by-step explanation:

In this question, we are asked to find the other 3 angles in an intersection.

Please check attachment for what the diagram of the intersection might look like.

The intersection consists simply of 4 angles meeting at a point with the 2 angles on each side vertically opposite to the angles on the other side.

since one of the angles is 55, and we are having a straight line, the other angle would be 180-55 = 125.[ sum of angles on a straight line is 180]

These two angles are vertically opposite, this means that the other three angles are 55,125 and 125.

3 0

3 years ago

Health insurance benefits vary by the size of the company (the Henry J. Kaiser Family Foundation website, June 23, 2016). The sa

xxMikexx [17]

Answer:

$\chi^2 = \frac{(32-42)^2}{42}+\frac{(18-8)^2}{8}+\frac{(68-63)^2}{63}+\frac{(7-12)^2}{12}+\frac{(89-84)^2}{84}+\frac{(11-16)^2}{16}=19.221$

Now we can calculate the degrees of freedom for the statistic given by:

$df=(rows-1)(cols-1)=(3-1)(2-1)=2$

And we can calculate the p value given by:

$p_v = P(\chi^2_{2} >19.221)=0.000067$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.221,2,TRUE)"

Since the p values is higher than a significance level for example $\alpha=0.05$ , we can reject the null hypothesis at 5% of significance, and we can conclude that the two variables are dependent at 5% of significance.

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

Assume the following dataset:

Size Company/ Heal. Ins. Yes No Total

Small 32 18 50

Medium 68 7 75

Large 89 11 100

_____________________________________

Total 189 36 225

We need to conduct a chi square test in order to check the following hypothesis:

H0: independence between heath insurance coverage and size of the company

H1: NO independence between heath insurance coverage and size of the company

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{total col * total row}{grand total}$

And the calculations are given by:

$E_{1} =\frac{50*189}{225}=42$

$E_{2} =\frac{50*36}{225}=8$

$E_{3} =\frac{75*189}{225}=63$

$E_{4} =\frac{75*36}{225}=12$

$E_{5} =\frac{100*189}{225}=84$

$E_{6} =\frac{100*36}{225}=16$

And the expected values are given by:

Size Company/ Heal. Ins. Yes No Total

Small 42 8 50

Medium 63 12 75

Large 84 16 100

_____________________________________

Total 189 36 225

And now we can calculate the statistic:

$\chi^2 = \frac{(32-42)^2}{42}+\frac{(18-8)^2}{8}+\frac{(68-63)^2}{63}+\frac{(7-12)^2}{12}+\frac{(89-84)^2}{84}+\frac{(11-16)^2}{16}=19.221$

Now we can calculate the degrees of freedom for the statistic given by:

$df=(rows-1)(cols-1)=(3-1)(2-1)=2$

And we can calculate the p value given by:

$p_v = P(\chi^2_{2} >19.221)=0.000067$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.221,2,TRUE)"

Since the p values is higher than a significance level for example $\alpha=0.05$ , we can reject the null hypothesis at 5% of significance, and we can conclude that the two variables are dependent at 5% of significance.

3 0

4 years ago