<span>In Drosophila + indicates wild-type allele for any gene, m is mahogany and e is ebony.
Female parents are m+/m+ and males are +e/+e.
F1 are m+/+e, all wild type. F1 females are crossed with me/me males - the test cross.
Offspring will be : non recombinant m+/me, mahogany wild type or +e/me wild type ebony. OR
recombinant me/me mahogany ebony or ++/++ wild type.
As the two genes are 25 map units apart, the percentage of recombinants will be 25% and therefore percentage parental types will be 75%.
75% 1000 is 750. There are two parental types, so you would expect 375 of each. Therefore, you would expect 375 m+/me and 375 +e/me.
25% of 1000 is 250 split between two recombinants =125 of each. Therefore you would expect 135 me/me and 125 ++/++</span>
Answer:
true
Explanation:
Daylight hours are shortest in each hemispheres winter. between summer and Winter Solstice, the number of daylight hours decreases, and the rate of decrease is larger the higher latitude. the fewer sunlight hours the colder the nights.
Cells build carbohydrate polymers by using energy to form glycosidic linkages, the bonds between monosaccharides. A dehydration synthesis reaction forms a bond between carbon atoms in two monosaccharides, sandwiching an oxygen atom between them and releasing a water molecule. Hope this helps!
Over utilized plants and animals are those plants and animals which are almost going out of existence or are already extincts as a result of over use by humans. Examples of over utilized animals include: West African Black Rhinoceros, Passenger pigeon, Sea mink, Tecopa pupfish, Pyrenean ibex and Tasmanian tiger.
The correct answer is: marsupials.
Marsupials are actually defined by their ability to hold the young in the pouches, where they can be well protected. Some examples are Kangaroos and Koalas.
Other answers are wrong: for example, gymnosperms are plants, not animals.
