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3 years ago

What is number 1 and 2

Mathematics

1 answer:

ioda3 years ago

6 0

yes the number is is proportional . 3$ a rose in sets of 3 and up . that give you a price for 15 at 45 $ so the cost of 30 Rose's would be 90$.

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What is the equation of the line that passes through the point (-5,-2) and has a slope of -6/5

tatyana61 [14]

Answer:

The answer is

Step-by-step explanation:

To find an equation of a line in point slope form when given the slope and a point we use the formula

$y - y_1 = m(x - x_1) \\$

where

m is the slope

( x1 , y1) is the point

From the question the point is (-5,-2) and the slope is - 6/5

The equation of the line is

$y + 2 = - \frac{6}{5} (x + 5) \\ y + 2 = - \frac{6}{5} x - 6 \\ y = - \frac{6}{5} x - 6 - 2$

We have the final answer as

$y = - \frac{6}{5} x - 8 \\$

Hope this helps you

5 0

3 years ago

Tickets for the homecoming dance cost $ 6 in advance and $ 10 at the door. The homecoming committee sells tickets in advance and

dusya [7]

Answer:

2050=6x+10x

Step-by-step explanation:

5 0

3 years ago

If A and B are independent events with P(A) = .5 and P(B) = .2, find the following:a) P(A U B)b) P(A^c ? B^c)c) P(A^c U B^c)**No

Effectus [21]

If A and B are independent, then $P(A\cap B)=P(A)P(B)$ .

$P(A\cup B)=P(A)+P(B)-P(A\cap B)=P(A)+P(B)-P(A)P(B)$

$P(A\cup B)=0.5+0.2-0.5\cdot0.2$

$\boxed{P(A\cup B)=0.6}$

b. I'm guessing the ? is supposed to stand for intersection. We can use DeMorgan's law for complements here:

$P(A^c\cap B^c)=P(A\cup B)^c=1-P(A\cup B)$

$P(A^c\cap B^c)=1-0.6$

$\boxed{P(A^c\cap B^c)=0.4}$

c. DeMorgan's law can be used here too:

$P(A^c\cup B^c)=P(A\cap B)^c=1-P(A\cap B)=1-P(A)P(B)$

$P(A^c\cup B^c)=1-0.5\cdot0.2$

$\boxed{P(A^c\cup B^c)=0.9}$

4 0

3 years ago

What an expression that is equivalent to 7/8

diamong [38]

Answer:

0.875 is the equivalent fraction

4 0

2 years ago

please help me with this IXL i only have an hour like i said on my last question and please tell me how to get the answer so i c

damaskus [11]

It is y=2x-6. Anymore questions?

3 0

3 years ago

Read 2 more answers