What is the equation in point slope form of the line that passes through the point (–1, –3)(–1, –3) and has a slope of 4?

1 answer:

6 0

The equation ofa line that passes throug (x1,y1) and has s slope of m is
y-y1=m(x-x1)

given
point is (-1,-3) and slope=4

y-(-3)=4(x-(-1)) or
y+3=4(x+1)

B is the answer

You might be interested in

The temperature at sunrise was -3*F. By noon, the temperature climbed 18 degrees. By sundown the temperature was -14*F. How much

Natalija [7]

Answer:

32*F

Step-by-step explanation:

* = degrees

Started at -3*F

By noon, the temperature climbed 18* = +18*

By sundown the temperature was -14*F

What we want to know: How much did the temperature drop between noon and sundown?

This is actually really easy!

What was the temperature at noon? --> 18*F

What was the temperature at sundown? --> -14*F

So what is the difference between 18* and -14*? We can't use an equation, so we will solve manually.

The distance from -14 to 0 is 14 degrees. Keep that in mind.

The distance from 18 to 0 is 18 degrees. Keep that in mind.

So what is 14 + 18? 14 + 18 = 32*.

So, the temperature dropped 32*F between noon and sundown.

I hope this helps! I know this was a little messy, but that is because we couldn't use an equation/expression to solve this.

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

6 0

3 years ago

Solve for h.

Luden [163]

Solving for h means we write the equation in such a way that h is isolated from other variables. It is done as follows:

(P = mgh) 1/mg
P/mg = mgh/mg
h = P/mg

Therefore, the correct answer from the choices listed above is option C, h = p/mg.

Hope this answers the question. Have a nice day.

4 0

3 years ago

in the given figure, AB//PQ//CD. AB = x units. CD = y units and PQ = z unites. Prove that 1/x + 1/y = 1/z

Arlecino [84]

12. ∆ABD is similar to ∆PQD, so
QD/z = BD/x
Likewise ∆CDB is similar to ∆PQB, so
QB/z = BD/y

Since QD + QB = BD, you have
QD/z + QB/z = BD/x + BD/y
BD/z = BD/x + BD/y
Dividing by BD gives the desired result:
1/x + 1/y = 1/z

13. Triangles ABD, BCD, and ACB are all similar. This means
AB/AC = AD/AB
AB² = AC×AD = (4 cm)×(9 cm)
AB² = 36 cm²
AB = 6 cm
and
BD/CD = AD/BD
BD² = CD×AD = (5 cm)×(4 cm)
BD² = 20 cm²
BD = 2√5 cm

7 0

3 years ago

Triangle S R Q is shown. Angle S R Q is a right angle. An altitude is drawn from point R to point T on side S Q to form a right

Jet001 [13]

Answer:

Option B.

Step-by-step explanation:

It is given that ΔSRQ is a right angle triangle, ∠SRQ is right angle.

RT is altitude on side SQ, ST=9, TQ=16 and SR=x.

In ΔSRQ and ΔSTR,

$m\angle S=m\angle S$ (Reflexive property)