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AVprozaik [17]
4 years ago
13

Find the circumference of the circle. Use 3.14 for pi. Round to the nearest unit. A picture of a circle with a line across the m

iddle like -------------- evenly and on the bottom it says 13 cm. PLS HELP
Mathematics
1 answer:
hoa [83]4 years ago
7 0
HEYA!!!!

Since the Diameter is 13 cm
So,radius is half of it I 6.5 cm

So applying formula,

2 \times \pi \times r
2 \times 3.14 \times 6.5
40.82

so rounding off it comes 41.

Hope the answer is correct.

Plz Mark as the brainliest....

:)
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10a.f(x) = x - 4
       h(x) = \sqrt{x - 5}
       (f - h)(6) = (6 - 4) - (\sqrt{6 - 5})
       (f - h)(6) = 2 - \sqrt{1}
       (f - h)(6) = 2 - 1
       (f - h)(6) = 1

10b.f(x) = x - 4
       g(x) = \frac{1}{x - 3}
       (f * g)(x) = (x - 4)(\frac{1}{x - 3})
       (f * g)(x) = \frac{x - 4}{x - 3}
       Domain: (-∞, 3) ∨ (3, ∞) {x|x ≠ 3}
       Interval Notation: (3 < x < 3), (3 > x > 3)

10c.g(x) = \frac{1}{x - 3}
       h(x) = \sqrt{x - 5}
       (g * h)(x) = (\frac{1}{x - 3})(\sqrt{x - 5})
       (g * h)(x) = \frac{\sqrt{x - 5}}{x - 3}

10d.f(x) = x - 4
       g(x) = \frac{1}{x - 3}
       h(x) = \sqrt[3]{x - 7}
       h(x) = (f * g)(x)
       \sqrt[3]{x - 7} = (x - 4)(\frac{1}{x - 3})
       \sqrt[3]{x - 7} = \frac{x - 4}{x - 3}
       (\sqrt[3]{x - 7})^{3} = (\frac{x - 4}{x - 3})^{3}
       x - 7 = \frac{(x - 4)^{3}}{(x - 3)^{3}}
       (x - 3)^{3}(x - 7) = (x - 4)^{3}
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       x^{4} - 16x^{3} + 90x^{2} - 216x + 189 = x^{3} - 12x^{2} + 48x - 64
       x^{4} + 90x^{2} - 216x + 189 = 17x^{3} - 12x^{2} + 48x - 64
       x^{4} + 102x^{2} - 216x + 189 = 17x^{3} + 48x - 64
       x^{4} + 102x^{2} + 189 = 17x^{3} + 264x - 64
       x^{4} + 102x^{2} + 253 = 17x^{3} + 264x
       x^{4} - 17x^{3} + 102x^{2} - 264x + 253 = 0
       x = 4\ or\ 8
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