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babymother [125]

3 years ago

11

If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen

t to y from the first equation is substituted into the second equation.
6x − y = 1
4x − 3y = −11

4(−6x + 1) − 3y = −11
4(6x + 1) − 3y = −11
4x − 3(6x − 1) = −11
4x − 3(−6x − 1) = −11

1 answer:

ozzi3 years ago

7 0

<u>Answer:</u>

<em>Equation is 4x-6(6x-1) = -11 </em>

<u>Step-by-step explanation:</u>

<em>The set of equations given are </em>

<em>6x-y=1 </em>

<em>4x-3y=-11 </em>

A pair of linear equations in <em>two variables x and y is given</em> in the set of equations. If there are two variables we require two equations to find the <em>value of variables</em>. Substitution is one among the methods used to solve pair of linear equations in two variables.

Here we have to <em>determine the value of y</em> from the first equation and then substitute it in the second equation.

<em>6x-y=1 </em>

<em>y=6x-1 </em>

<em>Substituting this value in second equation 4x-6y=-11 </em>

<em>we get </em>

<em>4x-6(6x-1) = -11 </em>

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shepuryov [24]

<h2>Hello!</h2>

The answers are:

First image:

The answer is the second option, the angles is $53\°$

Second image:

The answer is the third option:

$\frac{5}{13}$

Third image:

The length of the adjacent leg is the first option:

$8\sqrt{2}units$

Fourth image:

The answer is the fourth option, $72\°$

Fifth image:

The answer is the fourth option, DF (hypothenuse) is equal to 25 units.

<h2>Why?</h2>

To solve these problems, we need to use the following trigonometric identities and the Pythagorean Theorem, since we are working with right triangles.

$Tan(\alpha)=\frac{y}{x}\\\\(Tan(\alpha))^{-1} =(\frac{y}{x})^{-1}\\\\\alpha =Arctan(\frac{y}{x})$

$Sin(\alpha)=\frac{opposite}{hypothenuse}$

Pythagorean Theorem:

$c^{2}=a^{2} +b^{2}$

So, solving we have:

First image:

We are given a right triangle that has the following lengths:

$base=x=6units\\height=y=8units\\hypothenuse=10units$

Then, calculating we have:

$\alpha =Arctan(\frac{y}{x})\\\\\alpha =Arctan(\frac{8}{6})\\\\\alpha =Arctan(1.33)\\\\\alpha =53\°$

Hence, the answer is the second option, the angles is $53\°$

Second image:

We are given a right triangle that has the following lengths:

$base=x=12units\\height=y=5units\\hypothenuse=13units$

Then calculating the sin ratio, we have:

$Sin(\alpha)=\frac{opposite}{hypothenuse}$

$Sin(\alpha)=\frac{5}{13}$

Thence, the answer is the third option:

$\frac{5}{13}$

Third Image:

We are given the following information:

$hypothenuse=16units\\\\\alpha =45\°$

Then, calculating one of the angle legs, since both will have the same length, using the sine trigonometric identity, we have:

$Sin(\alpha)=\frac{Opposite}{Hypothenuse}\\ \\Sin(45\°)=\frac{Opposite}{16}\\\\Opposite=Sin(45\°)*16\\\\Opposite=\frac{\sqrt{2} }{2}*16=8\sqrt{2}$

Hence, the answer is the first option the length of the adjacent leg is

$Opposite=\frac{\sqrt{2} }{2}*16=8\sqrt{2}units$

Fourth image:

We are given the following information:

$base=x=9units\\height=y=3units$

To calculate the angle at the B vertex, first, we need to calculate the angle at the C vertex, and then, calculate the B vertex by the following way:

Since the sum of all the interior angles of a triangle are equal to 180°, we have that:

$180\°=Angle_{B}+Angle{C}+90\°$

$Angle_{B}=180\° -90\°-Angle_{C}$

So, calculating the angle at the C vertex, we have:

$\alpha =Arctan(\frac{y}{x})$

$\alpha =Arctan(\frac{3}{9})$

$\alpha =Arctan(0.33)=18.26\°$

Then, calculating the angle at the B vertex, we have:

$Angle_{B}=180\° -90\°-18.26\°=71.74\°=71.8\°=72\°$

Hence, the answer is the fourth option, $72\°$

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We are given the following information:

$base=x=24units\\height=y=7units$

Now, to calculate the distance DF (hypothenuse) we need to use the Pythagorean Theorem:

$c^{2}=a^{2} +b^{2} \\\\hypothenuse^{2}=adjacent^{2}+opposite^{2}\\\\\sqrt{hypothenuse^{2}}=\sqrt{adjacent^{2}+opposite^{2}}\\\\hypothenuse=\sqrt{adjacent^{2}+opposite^{2}}$

Then, substituting we have:

$hypothenuse=\sqrt{24^{2}+(7)^{2}}$

$hypothenuse=\sqrt{576+49}=\sqrt{625}$

$hypothenuse=\sqrt{625}$

$hypothenuse=25units$

Hence, the answer is the fourth option, DF (hypothenuse) is equal to 25 units.

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