What is the answer to this?

Simplify completely . x 2- 20x + 32 /x 2- 2x - 80

alina1380 [7]

This is usually considered to be the simplified form. The numerator zeros are irrational, so the numerator has no integer factors. The denominator zeros are x=-8, 10, but "simplified" usually means "multiplied out, rather than factored."

If you wanted to, you could write the expression as
.. 1 - (34/9)/(x -10) -(128/9)/(x +8)
This is more suitable for finding asymptotes and for doing integration, but may not be considered "simplified."

7 0

3 years ago

Scores of an IQ test have a bell-shaped distribution with a mean of and a standard deviation of . Use the empirical rule to det

Oduvanchick [21]

Complete question is;

Scores of an IQ test have a bell-shaped distribution with a mean of 100 and a standard deviation of 13. Use the empirical rule to determine the following.

(a) What percentage of people has an IQ score between 87 and 113?

(b) What percentage of people has an IQ score less than 74 or greater than 126?

(c) What percentage of people has an IQ score greater than 139?

Answer:

A) 68% of the people had an IQ score between 87 and 113

B) 5% of the people had IQ scores less than 74 and greater than 126.

C) 0.15% had an IQ score greater than 139

Step-by-step explanation:

We are given;

Mean; x¯ = 100

Standard deviation; σ = 13

According to the empirical rule in statistics;

>> 68% of the data lies within one standard deviation of the mean

>> 95% of the data lies within two standard deviations of the mean

>> 99.7% of the data lies within three standard deviations

A) We want to find the percentage of people with an IQ score between 87 and 113.

Within one standard deviation, we have;

x¯ ± σ

>> (100 - 13), (100 + 13)

>> (87, 113) which is the range we are looking for.

Thus, 68% of the people had an IQ score between 87 and 113

B) we want to find percentage of people has an IQ score less than 74 or greater than 126.

Let's first find those who had between 74 and 126.

Let's use two standard deviations within the mean.

x¯ ± 2σ

>> (100 - (2×13)), (100 + (2×13))

>> (74, 126) which is the range we are looking for.

So percentage that have IQ scores between 74 and 126 is 95%

Thus;

Percentage of those who had less than 74 and greater than 126 is;

P = 1 - 95%

P = 5%

C) we want to find the percentage of people that had an IQ score greater than 139.

Let's use the z-score formula;

z = (x¯ - μ)/σ

z = (139 - 100)/13

z = 39/13

z = 3

This means it is 3 standard deviations above the mean.

Thus;

Since it's one side outside the mean, then;

Percentage of people with an IQ score greater than 139 = (1 - 99.7%)/2 = 0.3%/2 = 0.15%

5 0

3 years ago

Mean, median, and mode. easy! 19 points!

o-na [289]

The answer is the range. The outliner is anything that “lies outside.” Range is the highest#-lowest#. So 78-28 = 50, which is not close the numbers that occurred most often (in this case, the #s in the 30s).

3 0

3 years ago

Which function has an inverse that is also a function? B9X) = x^2+3 d(x) = -9 m(x) = -7x P(x) = X

ohaa [14]

B(x) has an inverse that is also a function.

7 0

3 years ago

The number of loaves of bread purchased and the total cost of the bread in dollars can be modeled by the equation c = 3. 5b. Whi

Allisa [31]

You can use the fact that number of breads purchased cannot be negative since a customer either buys them or not and usually do not sell to the shopkeeper.(if somehow they end up selling to shop owner, then yes that will go in negative, but we'll assume it is wrong in most cases as generally shop owners are there to sell stuffs).

The third table of values matches the equation and includes only viable solutions.

<h3>What is a viable solution here?</h3>

It is talking about those solutions which are seen in real world. As stated above, a customer either buys the bread or not, thus number of breads sold will be either positive or 0(in case of no selling). Thus, we cannot have number of breads as negative.

Such solutions which are correct in the real world context here are called here as viable solutions.

<h3>Checking one by one all the tables for them being matched with table and viability</h3>

For first table, the number of breads are in negative, thus it is not going to have viable solution.

For second table, we have:

b = 0 thus c = 3.5b = 3.5 times 0 = 0 which is correctly given in second column.

b = 0.5, thus c = 3.5b = 3.5 times 0.5 =1.75 which is correctly given.

b = 1, thus c= 3.5 times 1 = 3.5 which is correctly given

b = 2001.5 thus c = 3.5 times 2001.5 = 7005.25 which is not correctly given, thus wrong.

For third table, we have:

b = 0, thus $c = 3.5 \times 0 = 0$ , correctly given in second column.

b = 3, thus $c = 3.5 \times 3 = 10.5$ , correctly given.

b = 6, thus $c = 3.5 \times 6 = 21$ , correctly given.

b = 9, thus $c = 3.5 \times 9 = 31.5$ , correctly given.

Thus, the third table of values matches the equation and includes only viable solutions.

Learn more about purchasing to cost relation here:
brainly.com/question/13727919

8 0

3 years ago