Answer:
![f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx-4%7D%20%2C%20g%28x%29%3D6x%5E%7B2%7D%5Ctextrm%7B%20or%20%7Df%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D%2Cg%28x%29%3D6x%5E%7B2%7D%20-4)
Step-by-step explanation:
Given:
The function, ![H(x)=\sqrt[3]{6x^{2}-4}](https://tex.z-dn.net/?f=H%28x%29%3D%5Csqrt%5B3%5D%7B6x%5E%7B2%7D-4%7D)
Solution 1:
Let ![f(x)=\sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D)
If
, then,
![\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bg%28x%29%7D%20%3D%5Csqrt%5B3%5D%7B6x%5E%7B2%7D-4%7D%5C%5Cg%28x%29%3D6x%5E%7B2%7D-4)
Solution 2:
Let
. Then,
![f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}](https://tex.z-dn.net/?f=f%28g%28x%29%29%3DH%28x%29%3D%5Csqrt%5B3%5D%7B6x%5E%7B2%7D-4%7D%5C%5C%5Csqrt%5B3%5D%7Bg%28x%29-4%7D%3D%5Csqrt%5B3%5D%7B6x%5E%7B2%7D-4%7D%20%5C%5Cg%28x%29-4%3D6x%5E%7B2%7D-4%5C%5Cg%28x%29%3D6x%5E%7B2%7D)
Similarly, there can be many solutions.
I think you mean write in word format so yea
11.09
"Eleven and 9 hundredths"
To convert decimals to fractions first put the decimal over 1, multiply by ten for every number after the decimal point and simplify.
(11.09/1)(10)(10) *Because there are 2 numbers after the . 0 and 9*
1109/100
This will be the most simplified you can get it!
As a mixed number:
11 9/100
Follow these steps for the rest!
21.06
"twenty one and six thousandths"
1053/50
21 3/50
0.06
"six thousandths" or
"zero and six thousandths"
3/50
0.50
"fifty thousandths" or "five tenths" since 0.50=0.5
1/2
6.15
"six and fifteen thousandths"
123/20
6 3/20
7.41
"seven and fourty one thousandths"
741/100
7 41/100
I HOPE THIS HELPS
1/2 (8+4)= 6
1/2(-1+4)= 1.5
1/2 (2+4)= 3
1/2 (4+4)= 4
So the correct answer would be A(8)
Answer: the answer is 50
Step-by-step explanation: I got it right in the quiz
Answer:
x=2
Step-by-step explanation:
12-10=2