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3 years ago

Generate an integer. Explain the meaning of zero. Drop of 200 feet

Mathematics

1 answer:

dsp733 years ago

6 0

It depends how high it is

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PLEASE HELP IM DESPERATE precalculus. also 50 points!! please god help

kompoz [17]

Answer:

For B thru F these options will vary but here how you do it

B. Step 1 Draw the 4 Quadrants.

Then Draw the Triangle in the lower right quadrant which we call quadrant 4. Label the X axis as Adjacent and positive. Label the Y axis as Opposite and negative. Label the Slanted side as the hypotune and AS POSITVE SINCE HYPOTENUSE IS ALWAYS POSITIVE.

FOR C. IN QUADRANT 2, PLOT A POINT AT 0,12 AND AT (-5,0). CONNECT THE DOTS AND IT FORMS A TRIANGLE. Label the X axis as adjacent and negative and the y axis as positve and opposite and label the slanted side hypotunese and positive.

FOR D Draw a straight line along the x axis then draw a slanted line passing through (5,-1). In between them put the theta symbol in there.

The labeling is the same for C.

For E. Since tan must be positve and secant must be positve, our triangle must be in the 1st Quadrant. Draw any right triangle as long it is in the first quadrant

The x axis is adjacent and positve. The y axis is opposite and positve. The hypotenuse is the slanted side and it is positve.

For F. Since sin is negative and cos is positve the triangle is in the 4th quadrant. Draw any triangle in the 4th quadrant and the labeling is the same for Problem B.

2. We can find the sec of cos by flipping cosine.

$\cos( \frac{x}{y} ) = \sec( \frac{y}{x} )$

$\cos( \frac{1}{2} ) = \sec(2 )$

Sec is 2.

To find the cotangent, first let find the sin then tan.

We can use the identity

$\cos( {theta}^{2} ) + \sin( {theta}^{2} ) = 1$

Let plug in the number

$\cos( \frac{ {1}^{2} }{{2}^{2} } ) + \sin(x {}^{2} ) = 1$

$\cos( \frac{1}{4} ) + \sin(x {}^{2} ) = 1$

$\sin(x {}^{2} ) = 1 - \frac{1}{4}$

$\sin(x {}^{2} ) = \frac{3}{4}$

$\sin(x) = \frac{ \sqrt{3} }{ \sqrt{4} }$

$\sin(x) = \frac{ \sqrt{3} }{2}$

Since sin is negative, sin x=

$- \frac{ \sqrt{3} }{2}$

Now let apply the formula

$\frac{ \sin(x) }{ \cos(x) } = \tan(x)$

$\frac{ \frac{ - \sqrt{3} }{2} }{ \frac{1}{2} } = \tan(x)$

$- \sqrt{3}$

Now let find cotangent we can the reciprocal of

tan.

$\tan= - \sqrt{3}$

$\cot = - \frac{1}{ \sqrt{3} }$

Rationalize denominator

$\frac{ - 1}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } = \frac{ \sqrt -{ 3} }{3}$

cotangent equal

$- \frac{ \sqrt{ 3} }{3}$

4 0

3 years ago

C(n)=-6(-1/3) n-1 what’s the 2nd term in the sequence

Tpy6a [65]

Answer:

The second term is 3

Step-by-step explanation:

C(n)=-6(-1/3) n-1

The first term of the sequence

C(1) = -6(-1/3)1-1

C(1) = (2)-1

C(1) = 1

C(n)=-6(-1/3) n-1

The second term of the sequence

C(2) = -6(-1/3)2-1

C(2) = -6(-2/3)-1

C(2) = 4-1

C(2) = 3

5 0

3 years ago

Read 2 more answers

15)

Vilka [71]

Answer:

Corresponding

Step-by-step explanation:

3 0

3 years ago

The box-and-whisker plots show data for the test scores of four groups of students in the same class. Which plot represents data

bixtya [17]

Answer:

The answer is B.

Step-by-step explanation:

7 0

3 years ago

In a standard deck of cards what is the probability of choosing a red king replacing it and then choosing and then a club.

Vika [28.1K]

Answer:

1/104

Step-by-step explanation:

The probability of choosing a red king is 2/52 since there are only two red kings in a deck of 52 cards...the probability of choosing a club would be 13/52 since there are 13 club cardsin a deck of 52 cards

Therefore the probability of choosing both by replacing the king would be 2/52 × 13/52 giving us 1/104

3 0

2 years ago