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never [62]
4 years ago
5

How do you answer these type of questions?

Mathematics
1 answer:
svetoff [14.1K]4 years ago
7 0
The answer is B (ie. 1^2 = 1, 2^2 = 4...)
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3. Solve the system using substitution (1 point)
Flauer [41]
(B), (C) And (D) are right for the equation y = 8 - x but none of those are true in the second equation.
8 0
3 years ago
4y square + y - 45 when y=-5
kobusy [5.1K]

Given:

The expression is

4y^2+y-45

To find:

The value of the given expression when y=-5.

Solution:

We have,

4y^2+y-45

Putting y=-5, we get

4(-5)^2+(-5)-45

=4(25)-5-45

=100-50

=50

Therefore, the value of the given expression is 50 when y=-5.

7 0
3 years ago
What is the y-intercept of the function f(x) = -x + ? 이름 를 0 3​
ad-work [718]

Answer:

C. ⅓

Step-by-step explanation:

A function in slope-intercept form is written as f(x) = mx + b

Here, b represents the y-intercept.

So given the function, f(x) = -\frac{2}{9}x + \frac{1}{3}, the y-intercept (b) would obviously be ⅓.

y-intercept = ⅓

7 0
3 years ago
Erica plotted the three towns closest to her house on a graph with town AA at (9, 12), town BB at (9, 7) and town CC at (1, 1).
Sliva [168]
To compute the distance between the points, we can apply the distance formula as shown below.

d = \sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2} }

In which x₁ and x₂ are the x-coordinates and y₁ and y₂ are the y-coordinates of the two points. Thus, applying this with the segments AABB, AACC, and BBCC, we have

\overline{AABB} = \sqrt{(9-9)^{2} + (12-7)^{2}} = 5
\overline{AACC} = \sqrt{(9-1)^{2} + (12-1)^{2}} = \sqrt{185}
\overline{BBCC} = \sqrt{(9-1)^{2} + (7-1)^{2}} = 10

Now that we have the lengths of all the sides of ΔAABBCC, we can find the missing angles using the Law of Cosines.

Generally, we have

c^{2} = a^{2} + b^{2} - 2abcosC

or

C = cos^{-1} (\frac{a^{2} + b^{2} - c^{2}}{2ab})

Hence, we have

\angle AA = cos^{-1} (\frac{(\sqrt{185})^{2} + 5^{2} - 10^{2}}{2(5)(\sqrt185)})
\angle BB= cos^{-1} (\frac{5^{2} + 10^{2} - (\sqrt{185})^{2}}{2(5)(10)})
\angle CC= cos^{-1} (\frac{10^{2} + (\sqrt{185})^{2} - 5^{2}}{2(5)(\sqrt{185})})

Simplifying this, we have

\angle AA = 36.03^{0}
\angle BB = 126.87^{0}
\angle CC = 17.10^{0} 

Thus, from this, we can arrange the angles from smallest to largest: ∠CC, ∠AA, and ∠BB.

Answer: ∠CC, ∠AA, and ∠BB
3 0
3 years ago
A common tangent is<br><br> segment CD<br> segment ST<br> segment RU
alex41 [277]

a tangential line to a circle is one that "touches" the circle but doesn't go inside, and keeps on going, in this case that'd be CD.

7 0
3 years ago
Read 2 more answers
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