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3 years ago

Any one know how to find the roots of an equation?

Mathematics

1 answer:

soldier1979 [14.2K]3 years ago

6 0

So what you do is
make into ax^2+bx+c=0 form

add-9/2 to both sides
y^2-2y+9/2=0
now we use the quadratice formula which is
x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$

ax^2+bx+c=0
1y^2-2y+9/2
a=1
b=-2
c=9/2
subsitute
x= $\frac{-(-2)+/- \sqrt{(-2)^{2}-4(1)(9/2)} }{2(1)}$
x= $\frac{2+/- \sqrt{4-(36/2)} }{2}$
x= $\frac{2+/- \sqrt{4-(18)} }{2}$
x= $\frac{2+/- \sqrt{-14} }{2}$
x= $\frac{2+/- \sqrt{-14} }{2}$
x= $1+/- \frac{\sqrt{-14} }{2}$
x= $1+/- \frac{\sqrt{14} \sqrt{-1}}{2}$
x= $1+/- \frac{\sqrt{14} i }{2}$
x= $1+/- \frac{ i \sqrt{14} }{2}$

answer is C

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See attachment for illustration

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