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Ronch [10]
3 years ago
11

Any one know how to find the roots of an equation?

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
6 0
So what you do is
make into ax^2+bx+c=0 form

add-9/2 to both sides
y^2-2y+9/2=0
now we use the quadratice formula which is
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

ax^2+bx+c=0
1y^2-2y+9/2
a=1
b=-2
c=9/2
subsitute
x=\frac{-(-2)+/- \sqrt{(-2)^{2}-4(1)(9/2)} }{2(1)}
x=\frac{2+/- \sqrt{4-(36/2)} }{2}
x=\frac{2+/- \sqrt{4-(18)} }{2}
x=\frac{2+/- \sqrt{-14} }{2}
x=\frac{2+/- \sqrt{-14} }{2}
x=1+/- \frac{\sqrt{-14} }{2}
x=1+/- \frac{\sqrt{14} \sqrt{-1}}{2}
x=1+/- \frac{\sqrt{14} i }{2}
x=1+/- \frac{ i \sqrt{14} }{2}

answer is C



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Given:

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\text{If for every } \epsilon>0\text{ there exists a }\delta >0\text{ such that}\\|f(x)-L|

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When ε = 0.01,   δ = 0.01

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