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AlexFokin [52]
3 years ago
12

PLEASE HELPP MEEEEE

Mathematics
1 answer:
pav-90 [236]3 years ago
6 0
The smallest region that can be photographed is
5*7 = 35 square km
so we want to know how long it takes to zoom out to an area of
35 * 5 = 175 square km.

Notice that the length and width increase at the same rate, 2 km/sec, and they start out with a difference of two, so when the width has increased from 5 to x, the length will have increased from 7 to x+2. At the desired coverage area, then,
x(x+2) = 175
x^2 + 2x = 175
x^2 + 2x + 1 = 176 [completing the square]
(x+1)^2 = 176
x+1 = ±4√11
x = -1 ±4√11

Since a negative value for x is meaningless here, x must be
-1 + 4√11 = about 12.27 km
and the time it took to increast to that value was
(12.27 - 5) km / (2 km/sec) = about 3.63 seconds
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4 0
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The rest of the question is the attached figure

========================================

solution:

========

As show in the attached figure


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∠O = ∠S = 36°


∴ Δ MNO is similar to Δ RTS


So, the correct statement:


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3 years ago
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\boxed{11\div3}
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