Answer:
±11 is the answer........
Answer is the third one. It is the only answer where all points work in the equation.
Answer: third choice
For question 1)
During the 8-9 , Mr hare travel 40miles
For the time 9 onwards they travel concurrently,
Let x be the distance covered by both since they can only meet if they covered the sams distance,
x/50 = x/40 -1 ,where the 1 is the (8-9) 1 hr
x/40 - x/50 = 1
x = 200
Time take by Mr Hare = 200/ 40 = 5
from 8 add 5 hours will be 1
ans is b
2)
during 8- 9 hare travelled 50miles
let x be the distance
x/55= x/50-1
x/50-x/55=1
x=550miles
time taken by hare = 550/50=11 hr
ie when they first meet it will be 7pm
so ans is b 8
<span>Remember the ratios
Linear = a : b
Area = a^2 : b^2
Volume = a^3 : b^3
Hence area ratios are 1008 : 1372
Becomes linear ratios of Sqrt(1008) : sqrt(1372) :: 31.749 : 37.040
Volume ratios becomes 31.749^3 : 37.040^3 :: 32002.96 : 50817.46
Hence
32002.96 / 50817.46 = Vol (S) / 1801 cm^3
Vol(s) = 32002.96 X 1801 / 50817.46 = 1134.20cm^3 ( nearest hundredth).
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