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ankoles [38]
3 years ago
8

Write an equation in point-slope form.

Mathematics
1 answer:
adoni [48]3 years ago
5 0
First: let (8,3) be the coordinates of the point A
so equation of straight: y-yA=slope(x-xA)
y-3=6(x-8)
second: y-yB=slope(x-xB)
y-(-5)=-2/5(x-(-3))
y+5=-2/5(x+3)
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If r(x)=3x-1 and s(x)=2x+1, which expression is equivalent to (r-s)(6)
daser333 [38]

Answer:

4

Step-by-step explanation:

Step 1:  find (r- s) or  r(x) - s(x)

 r(x) - s(x) = 3x - 1 - (2x + 1)

       r(x) - s(x) = 3x - 1 - 2x - 1   (distribute the -1 to 2x and 1)

           r(x) - s(x) =  x - 2        (combine like terms, 3x + (-2x) = x, -1 + (-1) = -2)

          so   r(x) - s(x) = x - 2, or   (r - s)(x) = x - 2

Step 2:  Plug in 6 to 'x' and find (r - s)(x)

  (r - s)(6) =  6 - 2   =   4

5 0
3 years ago
A furnace operates at 2,300°F.
Cloud [144]

Answer:

T = 2,300 + q × 250

6 0
3 years ago
What is the ratio of 420kg and 450kg
Anuta_ua [19.1K]
The answer is 42kg/45kg or 14kg/15kg
5 0
3 years ago
What is the value of x?
Serjik [45]

Answer:

  x = 32

Step-by-step explanation:

Each angle of the equilateral triangle is 60°.

  (2x -4)° = 60°

  x -2 = 30 . . . . . . divide by 2°

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__

  5y° = 60°

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7 0
3 years ago
Show all work to identify the asymptotes and state the end behavior of the function f(x)=5x/x-25
Nina [5.8K]

Using the asymptote concept, it is found that:

  • The vertical asymptote is of x = 25.
  • The horizontal asymptote is of y = 5.
  • Considering the horizontal asymptote, it is found that the end behavior of the function is that it tends to y = 5 to the left and to the right of the graph.

<h3>What are the asymptotes of a function f(x)?</h3>

  • The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
  • The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

f(x) = \frac{5x}{x - 25}

Considering the denominator, the vertical asymptote is:

x - 25 = 0 -> x = 25.

The horizontal asymptote is found as follows:

y = \lim_{x \rightarrow \infty} f(x) = \lim_{x \rightarrow \infty} \frac{5x}{x - 25} = \lim_{x \rightarrow \infty} \frac{5x}{x} = \lim_{x \rightarrow \infty} 5 = 5

Hence the end behavior of the function is that it tends to y = 5 to the left and to the right of the graph.

More can be learned about asymptotes and end behavior at brainly.com/question/28037814

#SPJ1

6 0
2 years ago
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