Answer:
hi! i’m pretty sure it’s -18 and -20
Step-by-step explanation:
Answer:
Step-by-step explanation:
here you go mate'
step 1
11 = y-6 equation
step 2
11+6=y-6+6 add 6 to the sides
answer
y=17
can i get brainliest if you dont mind?
We know that , in a circle radius perpendicular to chord will bisect the chord.
OM=18, so OQ=QM=18/2=9.
Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
<em><u>Answer:</u></em>
<em><u>Answer:If any of the inequalities in the compound OR inequality have a valid solution, the compound OR inequality will also have a valid solution. The inequality below has no solutions because x^2 + 1 is never less than 0 and -x^2 - x - 2 is never greater than 0.</u></em>
Answer:
(-30, 10)
multiply -20/60 by -0.5 each and you get 10/-30
this is the only pair achievable by proportion.
