750w+1000 < 20,000
(750$ a week, plus the one time ad cost of 1000$ has the be LESS than the budget of 20,000)
Answer:
Check Explanation
Step-by-step explanation:
5b = 25 (equation)
5b (neither)
5(3+4) (expression)
Answer:

Step-by-step explanation:
Assuming conditions are met, the formula for a confidence interval (CI) for the difference between two population proportions is
where
and
are the sample proportion and sample size of the first sample, and
and
are the sample proportion and sample size of the second sample.
We see that
and
. We also know that a 98% confidence level corresponds to a critical value of
, so we can plug these values into the formula to get our desired confidence interval:

Hence, we are 98% confident that the true difference in the proportion of people that live in a city who identify as a democrat and the proportion of people that live in a rural area who identify as a democrat is contained within the interval {-0.2941,-0.0337}
The 98% confidence interval also suggests that it may be more likely that identified democrats in a rural area have a greater proportion than identified democrats in a city since the differences in the interval are less than 0.
2475 different teams can be formed.
Combination is the way in which items can be selected from a collection. If we have n total objects and r objects want to be selected, the number of combinations is:

Since we need to nominate 2 men from a company of 10 males, the number of ways this can be done = 
Also, we need to nominate 2 women from a company of 11 females, the number of ways this can be done = 
Therefore the total number of different teams that can be formed = 45 ways * 55 ways = 2475 ways
Find more at: brainly.com/question/8018593
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