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Yanka [14]
3 years ago
13

For what value of p will the pair of linear equations have infinitely many solutions (p-3)x + 3y = p , px+ py = 12

Mathematics
1 answer:
sleet_krkn [62]3 years ago
5 0

Answer: p = 6


Step-by-step explanation:

HI !


 px + 3y - ( p-3)=0


a₁ = p , b₁ = 3 , c₁ = - (p-3)


=====================


12x + py - p=0


a₂ = 12  , b₂ = p , c₂ = -p


since , the equations have infinite solutions , 


a₁/a₂ = b₁/b₂ = c₁/c₂


p/12 = 3/p =  p-3/p



--------------------------------------


p/12 = 3/p


cross multiply ,


p² = 36


p = √36

 p = 6


for the value of p = 6 , the equations will have infinitely many solutions





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7 7/8 can be estimated to 8

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7 7/8 = 56+7/8 = 63/8

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<em>Add- </em>

0.859+1.63=2.489

<em>Subtract-</em> (Not sure where the decimal was)

0.859-0.03=0.829

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<em>Multiply-</em>

0.859*10^1=8.59

0.859*10^2=85.9

0.859*10^3=859

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<em>Divide-</em>

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<em>Round-</em>

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We can calculate the required probability by using the binomial distribution, but it's easier to calculate the probability of the negated event an subtract from 1.

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