Your free ride to work ends in 14 days. So, maybe you need a car? How much can you afford to spend? Below is what's available at
a dealership near you. Which car should you buy? Before you decide, think about this: You do not have enough money in your account to buy a car. You'll have to finance your purchase. You'll have to put down 25% of the vehicle's selling price as a down payment.
1 answer:
Step-by-step explanation:
Kindly find attached a screenshot of the price list of some cars from motor 1 .com since you did not provide any in the question, and let us assume it is the same as what is available at a dealership near you.
From the list, since you don't have enough money in your account to buy a car, I will say you should get a 2017 Nissan Versa for $11,990
and 25% of $11,990 is
(25/100)* 11,990
0.25* 11,990
$2997.5
So you can make a down payment of $2997.5
and pay the remainder of $8992.5 later
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9514 1404 393
Answer:
A. 3×3
B. [0, 1, 5]
C. (rows, columns) = (# equations, # variables) for matrix A; vector x remains unchanged; vector b has a row for each equation.
Step-by-step explanation:
A. The matrix A has a row for each equation and a column for each variable. The entries in each column of a given row are the coefficients of the corresponding variable in the equation the row represents. If the variable is missing, its coefficient is zero.
This system of equations has 3 equations in 3 variables, so matrix A has dimensions ...
A dimensions = (rows, columns) = (# equations, # variables) = (3, 3)
Matrix A is 3×3.
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B. The second row of A represents the second equation:
The coefficients of the variables are 0, 1, 5. These are the entries in row 2 of matrix A.
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C. As stated in part A, the size of matrix A will match the number of equations and variables in the system. If the number of variables remains the same, the number of rows of A (and b) will reflect the number of equations. (The number of columns of A (and rows of x) will reflect the number of variables.)