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Helga [31]
3 years ago
13

Glucose is broken down during cellular respiration to produce carbon dioxide and

Biology
2 answers:
zubka84 [21]3 years ago
4 0
The answer is (D) water vapor
lubasha [3.4K]3 years ago
4 0

Answer:

The correct answer is D) water vapor.

Explanation:

During photosynthesis, plants make glucose from carbon dioxide and water with the help of sunlight. Respiration is opposite to photosynthesis in which the glucose is broken down into carbon dioxide and water.

Respiration occurs in both animals and plants which is required to provide energy to the system in the form of ATP. The carbon dioxide released during respiration is again taken by plants during photosynthesis to make glucose,

The reaction takes place during respiration is:

                       C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + ATP

Therefore the correct answer is D) water vapor.

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True or False: The following example populations meet the basic requirements of Hardy-Weinberg equilibrium. a. A small, isolated
Setler79 [48]

Answer:

Only option D is TRUE. The rest are FALSE.

Explanation:

In Hardy-Weinberg equilibrium, there is virtually no change in the frequency of alleles and genotype, in a population, meaning there is a genetic equilibrium in that population which shows no real evolutionary change has occurred. According to the , several conditions must be met before such equilibrium can be said to occur in a population, these requirements or conditions are:

1. There must be an unrestricted random mating

2. Mutation that results in the change of gene is absent

3. The population size must be large enough

4. Absence of migration,i.e. no movement of members out of a population or into a population

5. No natural selection

Now let’s take a  at the example of populations given, stating whether they meet the above listed conditions or not

For option A, which is “A small, isolated population of seals living in a stable environment with no genetic mutations” this is False, a small population size of seals is more likely to have its allele frequencies changed by random fluctuations compared to a large population size of seals. This does not satisfy condition number 3 listed above.

Option B, “A large population of fish where females mate with males based on size” is False. It does not satisfy condition number 1 listed above. In this population example, there is restricted random mating.

Option C “A population of birds with no genetic mutations that often mate with members of neighboring bird populations” is False. It does not meet condition 4, because there is exchange of genes with other populations that might have different allele frequencies.

Option D “A large, isolated population of squirrels that lives in a stable environment, has no genetic mutations, and mates randomly” is True. This meets all conditions listed above.

Option E “A large population of spiders that experiences immigration from a second nearby population” is False. This does not meet condition 4.

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3 years ago
Ways of conserving soil fertility ​
user100 [1]

Deforestation effects soil quality and desertification will also effect the soils fertility. hope this helps :)

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The population from which the researcher selects the actual study sample is referred to as the: a accessible population. b scien
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The answer is a. accessible population because an accessible population is the portion of the target population to which the researcher has reasonable access.
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A titratable group is in the active site of an enzyme and must be protonated for the enzyme to function. Assume that the group h
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Answer:

The correct option is 3. "At pH 6.5 the enyzme is 50% active"

Explanation:

For the titratable group to be protonated and cause the enzyme to be in the active state, it needs to have gained a hydrogen cation (H+). In order for that to happen, there must be enough hydrogen cations in the environment of the enzyme, and hence, an acidic pH is required in this case.

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