The plane must be 3.38 miles away from the runway to begin the descent. The equation I used was "y = -0.1111111x + 0.3755682", 0.37~ being the height in feet (in miles) and -0.11~ being the descent. The x-intercept is located at 3.38.
This is the net of a rectangular prism, so the surface area can be found with the formula: SA=2lw+2wh+2lh
In this case,
l=10.5
w=6.4
h=4
Now, we can plug these numbers into the equation:
SA= (2)(10.5)(6.4) + (2)(6.4)(4) + (2)(10.5)(4)
SA= 134.4 + 51.2 + 84
SA = 269.6 cm
Therefore, the answer is D.
Answer:
67 square units
Step-by-step explanation:
The area using the left-hand sum is the sum of products of the function value at the left side of the interval and the width of the interval.
<h3>Area</h3>
The attachment shows a table of the x-value at the left side of each interval, and the corresponding function value there. The interval width is 1 unit in every case, so the desired area is simply the sum of the function values.
The approximate area is 67 square units.
No it will never equal five