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Sholpan [36]
4 years ago
8

Which expression is equivalent to sec2xcot2x?

Mathematics
1 answer:
hram777 [196]4 years ago
5 0

Answer:

B. csc²(x)

Step-by-step explanation:

You can use the relations ...

sec(x) = 1/cos(x)

csc(x) = 1/sin(x)

cot(x) = cos(x)/sin(x)

to replace the functions in your expression. Then you have ...

sec²(x)·cot²(x) = (1/cos(x)·cos(x)/sin(x))² = (1/sin(x))² = csc²(x)

___

Alternate solution

You can also use the relation

cot(x) = csc(x)/sec(x)

Then ...

(sec(x)·cot(x))² = (sec(x)·csc(x)/sec(x))² = csc²(x)

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9514 1404 393

Answer:

  -1/6

Step-by-step explanation:

A suitable calculator can evaluate this for you and show you the result as a fraction.

You start with the multiplication in the inner-most set of brackets. Here, those brackets are the absolute value function.

  -2(-1/3) = +2/3

Then the sum in those brackets:

  -5/6 +2/3 = -5/6 +4/6 = -1/6

The absolute value changes the sign of this back to positive, so the value in square brackets is ...

  3 -(1/6) = 18/6 -1/6 = 17/6

Finally, this value is divided by -17, so you have ...

  \dfrac{17}{6}\div(-17)=\dfrac{17}{6}\cdot\dfrac{-1}{17}=-\dfrac{17\cdot1}{17\cdot6}=\boxed{-\dfrac{1}{6}}

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3 years ago
What is the value of cos(infinity)?
Monica [59]
The problem ask to find the value of the cos(infinity) and the best answer, base on my further calculation and formulation that came up to a solution that leads me to an answer that the cos(infinity) is undefined but it has a range of (-1,1). I hope you are satisfied with my answer and feel free to ask for more 
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3 years ago
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Solve and check the following equation algebraically. 1/2(x + 32) = -10
ANTONII [103]
Solve :
1/2(x + 32) = -10....multiply both sides by 2
x + 32 = -10 * 2
x + 32 = -20
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x = - 52 <===

check :
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Use an addition property to solve for c.
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Answer:

"C" =14

Step-by-step explanation:

14+(-12)=-12+c

-12+c=14+(-12)

-12+c=14-12

-12+c+12=2+12

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Answer:

7.3

Step-by-step explanation:

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Distance = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

X2 is 7 (X coordinate of school)

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7 - 5 = 2

2^2 = 4

Y2 is 7 (Y coordinate of school)

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