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Bas_tet [7]
3 years ago
6

Explain how an estimate helps you to place the decimal point when mutiplyning 3.9 times 5.3

Mathematics
2 answers:
kvv77 [185]3 years ago
7 0
It'll make it easier to multiply. If you round 3.9 to four, and 5.3 to five, it's quite easy to figure out the answer is about 20. I hope this helps! :)
Juli2301 [7.4K]3 years ago
6 0
You can round these numbers to the closes whole number; 3.9-->4 and 5.3-->5, and then you can do 5x4 to get 20; and if you multiply regularly without estimating, your answer will be around 20.
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Find the mean of the data summarized in the given frequency distribution . Compare the computed mean to the actual mean of 57.6
AlexFokin [52]

The mean of the frequency distribution is 52.6° F. The computed mean of 52.6° F is lesser than the actual mean of 57.6° F.

<h3>What is the mean of a distribution?</h3>

The mean of the distribution can be defined as the average value of the distribution, It can be expressed as the total sum of all the observed values divided by the frequency of the distribution.

From the parameters given:

Low-temperature             Frequency

40 - 44                                    2

45 - 49                                    5

50 - 54                                    9

55 - 59                                    6

60 - 64                                    3

The first thing to do is to determine the class midpoint. The class midpoint is the sum of the class interval divided by 2.

The class midpoint of 40 - 44 is \mathbf{\dfrac{40 + 44}{2} = 42}

The class midpoint of 45 - 49 is \mathbf{\dfrac{45 + 49}{2} = 47}

The class midpoint of 50 - 54 is \mathbf{\dfrac{50 + 54}{2} = 52}

The class midpoint of 55 - 59 is \mathbf{\dfrac{55 + 59}{2} = 57}

The class midpoint of 60 - 64 is \mathbf{\dfrac{60 + 64}{2} = 62}

Now, the table can be represented as:

Low-temperature             Frequency          x  

40 - 44                                    2                   42

45 - 49                                    5                   47

50 - 54                                    9                   52

55 - 59                                    6                   57

60 - 64                                    3                   62

The mean can now be determined as follows:

\mathbf{\bar x = \dfrac{\sum fx}{\sum f }}

\mathbf{\bar x = \dfrac{(2 \times 42)+ (5 \times 47) + ( 9\times 52) +(6\times 57) + (3 \times 62)}{2 + 5 + 9 + 6 + 3 }}

\mathbf{\bar x = \dfrac{1315}{25}}

\mathbf{\bar x = 52.6}

Therefore, we can conclude that the mean of the frequency distribution is 52.6° F. The computed mean of 52.6° F. is lesser than the actual mean of 57.6° F

Learn more about the mean of frequency distribution here:

brainly.com/question/12269435

3 0
2 years ago
What is the domain…..
saul85 [17]

Answer:

(-00, 00)

Step-by-step explanation:

(-infinity, infinity)

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Answer:

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Answer:

x= 2

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Just subtract by like numbers.

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A square mosaic is made of small glass squares. If there are 196 small squares in the mosaic, how many are along an edge?
alexandr402 [8]
There would be 14 small glass squares along the edges of the square mosaic.  

This is because 14 * 14 = 196, which means that if each side length was 14 squares, that the area of the square would contain 196 squares.  
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3 years ago
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