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hammer [34]
3 years ago
12

How does an ALU perform a logical operation? A. It compares two conditions. B. It compares two additions. C. It compares two mul

tiplications. D. It compares two divisions. E. It compares two subtractions.
Computers and Technology
2 answers:
german3 years ago
6 0
A.It compares two conditions
Mashcka [7]3 years ago
3 0

Answer:

Option A is the correct answer for the above question.

Explanation:

ALU is used to operate on the computer system. It works on a instruction of CU (Control unit). CU gives the control to ALU that which operation is performed and how it is performed. ALU is of two type- first is AU and the other is LU. AU is used to perform Arithmetic operation while LU is used to perform Logical operation. The ALU performs logical operation by comparison the operands because logical operations gives the result either true or false which comes after comparison only.

The above question asked about the work of ALU then the option A is correct answer because it states about work of ALU while the other is not because--

  • Option B states that The ALU compares two addition but it compares any condition.
  • Option C states that The ALU compares two multiplications but it compares any condition.
  • Option D states that The ALU compares two divisions but it compares any condition.
  • Option E states that The ALU compares two subtractions but it compares any condition.

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Read 2 more answers
Given an array temps of double s, containing temperature data, compute the average temperature. Store the average in a variable
Ket [755]

Answer:

#include <iostream>

using namespace std;

// average function

void average(double arr[], int n) {

double total = 0;

double avgTemp;

for (int i = 0; i < n; i++)

{

 // find temperatures total

 total = total + arr[i];

}

// find average

avgTemp = total / n;

cout << "\nAverage Temperature = " << avgTemp << endl;

}

// print temps[] array

void printArray(double arr[], int n) {

for (int i = 0; i < n; i++)

{

 cout << arr[i] << "   ";

}

}

int main() {

int const k = 5;

double temps[k];

// temperature value

double tempValue;  

// Enter 5 temperatures of your choice

for (int i = 0; i < k; i++)

{

 cout << "Enter Temperature value " << i+1 << ": ";

 cin >> tempValue;

 temps[i] = tempValue;

}

// Function call to print temps[] array

printArray(temps, k);  

// Function call to print average of given teperatures

average(temps, k);        

return 0;

}

Explanation:

• Inside main(), int constant k is created to set the maximum size of array temps[].

• tempValue of  type double takes value at a given index of our temps[] array.

• the for loop inside main() is used to get tempValue from the user and store those values in our array temps[].

• after that printArray() function is called. to pass an array to a function it requires to perimeters 1) name of the array which is temps in our case. 2) maximum number of the index which is  k.

• note the syntax of void average(double arr[], int n). Since we are passing an array to the function so its formal parameters would be arr[] and an int n which specifies the maximum size of our array temps[].

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vichka [17]

Answer:

internetwork

Explanation:

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I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

3 0
3 years ago
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